Writing a find function
1 回表示 (過去 30 日間)
古いコメントを表示
Hello all,
I am trying to run a function that will use the "find" function to separate grades
i have my code below, but I dont know what I seem to be doing wrong.
function [out_orig, out_new] = parse_grades
scores = 100*rand(50,1);
ind1 = find(scores >= 90); %A
ind2 = find(scores <= 80) && ( scores < 90 ); % B
ind3 = find(scores <=70) && (scores < 80); % C
ind4 = find(scores <= 60) && ( scores <70); % D
ind5 = find (scores <60); % f
vec_new(ind1) = 'A';
vec_new(ind2) = 'B' ;
vec_new(ind3) = 'C' ;
vec_new(ind4) = 'D' ;
vec_new(ind5) = 'F';
out_orig = scores;
out_new = vec_new ;
end
the error I am getting is
Operands to the || and && operators must be convertible to logical scalar values.
Error in parse_grades (line 6)
ind2 = find(scores <= 80) && ( scores < 90 ); % B
回答 (1 件)
KSSV
2020 年 10 月 13 日
編集済み: KSSV
2020 年 10 月 13 日
You can proceed something like htis:
score = randperm(100,1)
if score >=90
grade = 'A' ;
elseif (score >= 80) & (score < 90 )
grade = 'B' ;
elseif (score >= 70) & (score < 80)
grade = 'C' ;
elseif (score >= 60) & (score < 70 )
grade = 'D' ;
else
grade = 'E' ;
end
grade
If you want score to be a vector, proceed like this:
score = randperm(100,10) ;
idx = zeros(size(score)) ;
idx(score >= 90) = 1 ;
idx(score >= 80 & score < 90) = 2 ;
idx(score >= 70 & score < 80) = 3 ;
idx(score >= 60 & score < 70) = 4 ;
idx(idx==0) = 5 ;
grade = {'A', 'B', 'C', 'D', 'E'} ;
iwant = grade(idx)
6 件のコメント
Stephen23
2020 年 10 月 13 日
"Can it be used it find?"
Using find is less efficient than the simple logical indexing that KSSV's answer shows.
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!