I'm trying to graph the function xye^(-(x.^2+y.^2)), and I used both surf and mesh to do so. Below is the code. The problem is the two graphs are different. The surf function seems to have gotten it correct, but the mesh function looks like it graphed the absolute value of the function. Why is there this difference?
clear
clc
r=100;
x1 = linspace(-10,10,r);
y2 = linspace(-10,10,r);
[x,y] = meshgrid(x1,y2);
z=x.*y.*exp(-(x.^2+y.^2));
figure
surf(x,y,z)
xlabel('x');
ylabel('y');
zlabel('z');
grid on
shading interp
colorbar
figure
mesh(x,y,z.^2)
xlabel('x');
ylabel('y');
zlabel('z');
grid on

 採用された回答

Adam Danz
Adam Danz 2020 年 10 月 5 日
編集済み: Adam Danz 2020 年 10 月 5 日

0 投票

> The problem is the two graphs are different. The surf function seems to have gotten it correct, but the mesh function looks like it graphed the absolute value of the function
Hint
mesh(x,y,z.^2)
% ^^^
Also see the difference in the z-axis values. The range of z values in the mesh version is not the absolute value of the z values in the surf version, it's squared (which forces negative values to be positive).

2 件のコメント

Nathan Shapiro
Nathan Shapiro 2020 年 10 月 5 日
Oh, I can't believe I missed that. Thank you for your help!
Adam Danz
Adam Danz 2020 年 10 月 5 日
Sometimes a 2nd pair of eye is all that's needed.

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