Transposing 5x5x5 matrix

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Özgür Alaydin
Özgür Alaydin 2020 年 9 月 24 日
コメント済み: Özgür Alaydin 2020 年 9 月 24 日
Hello all,
I am trying to transpose 5x5x5 matrix but then i get a warning and it says "use permute".
When use function like : permute(r,[5,5,5]) (r is 5x5x5 matrix).
I have this error:
Error using permute
ORDER contains an invalid permutation index.
How can i transpose this matrix? I need to transpose thise matrix and multply it with another 5x5x5 matrix. I have added the matrix.
Thanks for help

採用された回答

Stephen23
Stephen23 2020 年 9 月 24 日
new = permute(r,[2,1,3])
  1 件のコメント
Özgür Alaydin
Özgür Alaydin 2020 年 9 月 24 日
Thanks :)

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その他の回答 (1 件)

Ameer Hamza
Ameer Hamza 2020 年 9 月 24 日
編集済み: Ameer Hamza 2020 年 9 月 24 日
You need to specify the order of the dimensions after transpose. It should be something like this
permute(r, [2, 3, 1])
It means that after permute, the dimension which was at 2nd location will move to the 1st location, 3rd to 2nd, and 1st to the 3rd location.
For example, transpose is equivalent to
permute(M, [2 1]); % M is 2D matrix, this command is equivalent to transpose
  5 件のコメント
Ameer Hamza
Ameer Hamza 2020 年 9 月 24 日
Yes, then permute will return 5x5x5 matrix. You can then do element-wise multiplication.
Özgür Alaydin
Özgür Alaydin 2020 年 9 月 24 日
But permute(r,[5,5,5]) is not working. How can i do it?

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