# Reshape a multidimensional matrix

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elena galvano 2020 年 9 月 23 日 9:42
コメント済み: Steven Lord 2020 年 9 月 23 日 13:26
i have a multidimensional matrix (146x146x144) that i want to reshape (144x21316). the command reshape works "vertically", how i can reshape "horizontally" ( every rows next to another)

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### 回答 (2 件)

madhan ravi 2020 年 9 月 23 日 9:44

reshape(permute(matrix, [3, 2, 1]), 144, [ ])

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elena galvano 2020 年 9 月 23 日 10:56
i know what it is.. i told you that the first matrix is a multidimensional (146*146*144) and i want to reshape in a (144x21316). i showed to you that matrix to explain how i want to order the cells.
madhan ravi 2020 年 9 月 23 日 11:09
reshape(permute(matrix, [2, 1, 3]), 144, []).'
Steven Lord 2020 年 9 月 23 日 13:26
for examplei have a matrix
[ 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2 2 2 2
3 3 3 3 3 3 3 3 3 3]
That has one too many 3's in the last row. Correcting that problem:
A = [ 1 1 1 1 1 1 1 1 1;
2 2 2 2 2 2 2 2 2;
3 3 3 3 3 3 3 3 3];
P = reshape(A.', 1, [])
If your A array is actually a 3-dimensional (or generally N-dimensional for N > 2) you're going to want to use permute instead of the .' operator.
P2 = reshape(permute(A, [2 1]), 1, [])
To ask a similar question that madhan ravi did, for this specific array:
B = reshape(1:24, [2 3 4])
What exactly do you want the result of reshaping B to be? Give us the explicit command to create Breshaped:
Breshaped = [ % Fill in numbers here]
Once we know what you want Breshaped to be we can help you write the command to create it.

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KSSV 2020 年 9 月 23 日 9:45
iwant = reshape(144,[]) ;
Wont this work for you?

#### 1 件のコメント

elena galvano 2020 年 9 月 23 日 9:53
No, the command is wrong

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