sort a matrix without using sort function

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John
John 2013 年 1 月 22 日
コメント済み: Jan 2017 年 10 月 2 日
how can I sort this matrix in descend order(only columns) without using sort function (my homework). for example: A= [
17 24 1 8 15
23 5 7 14 16
4 6 13 20 22
10 12 19 21 3
11 18 25 2 9 ]
to
B=[
24 17 15 8 1
23 16 14 7 5
22 20 13 6 4
. . . . . .. . .
.. .. . .. . .. . ]
thanks
  3 件のコメント
John
John 2013 年 1 月 22 日
thanks for your help ,I was able to get this script work. thank your very much.
Cedric
Cedric 2013 年 1 月 22 日
+1 for the "homework" tag! If other students were as honest as that, they would get more of my time ;-)

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回答 (1 件)

Jan
Jan 2013 年 1 月 22 日
編集済み: Jan 2017 年 10 月 1 日
Here a solution, which I would not submit except with a bold explanation:
B = zeros(size(A));
n = size(A, 2);
for iRow = 1:size(A, 1)
v = A(iRow, :);
while any(diff(v) > 0) % Test if sorted in descending order
v = v(randperm(n, n)); % If not, shuffle the elements randomly
end
B(iRow, :) = v;
end
This is based on the "infinite monkey" theorem: Even a randomly typing monkey will find the solution by accident. In consequence is not guaranteed to finish until your homework is due.
[EDITED] This is not a serious suggestion. If you deliver this as solution of a homework, you might get an extra point for a nerdy kind of humor, perhaps. Ask an internet search engine for better sorting algorithms.
  6 件のコメント
Pame
Pame 2017 年 10 月 2 日
I like the insertion sort method, and i've got it to work for arrays, but not for matrixes.
Also currently trying to make a function which sorts matrixes in ascending order so that the lowest value element is in (1,1) and the highest value element is in the last row, last column.
Jan
Jan 2017 年 10 月 2 日
But "matrices" are "arrays". Do you mean "vectors"?
Do you have a question? If so, I recommend to open a new thread.

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