How can I sort a matrix to match another matrix?
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Hello everybody,
I have a question regarding the sorting. I have 2 matrices, A and B. For example:
A = [11 1; 12 1; 13 1; 21 2; 23 2; 31 3; 33 3; 41 4]
B = [1; 2; 1; 3; 1; 4; 2; 3]
How can I sort A (randomly each time) that the 2 column of A is same with B? Such as:
A = [12 1; 23 2; 11 1; 31 3; 13 1; 41 4; 21 2; 33 3]
Stay happy and healty..
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Stephen23
2020 年 9 月 16 日
>> [~,idx] = sort(B);
>> [~,idx(idx)] = sort(A(:,2));
>> A = A(idx,:)
A =
11 1
21 2
12 1
31 3
13 1
41 4
23 2
33 3
6 件のコメント
Stephen23
2020 年 10 月 17 日
編集済み: Stephen23
2020 年 10 月 17 日
"Do you have any idea that I can make this work?"
Possibly you could replace the RHS with a string (or character vector) of the number:
A(:,2) == num2str(k)
"...the first column contains strings, whereas second column is numbers."
I strongly recommend that you convert the data into a table, then the first column would be strings and the second column really would be numbers (not strings encoding numbers). Numeric data should be efficiently stored as numeric, which also makes processing it much easier.
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