How to (nicely) copy a structure array field into another

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Joan Vazquez
Joan Vazquez 2020 年 9 月 1 日
コメント済み: Ben 2024 年 4 月 18 日 12:56
Based on several questions in this forum, the following piece of code works. But I wonder if there is a more 'elegant' or 'neat' way in Matlab ('matlabish', 'matlabonic'...?)
% S is a given structure (I definetely can't modify that)
S(1).name = [];
S(2).name = [];
% Nicely stored input data (I could parse this differently, but this is not the point)
data(1).name = 'A';
data(2).name = 'B';
% Is there a more straightforward way to achieve 'S.name = data.name' ?
names = {data.name};
[S.name] = names{:};
% Or a clean one liner that avoids using 'names' ?

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Stephen23
Stephen23 2020 年 9 月 1 日
編集済み: Stephen23 2020 年 9 月 1 日
Matlabcalifragilisticexpialidocious:
[S.name] = deal(data.name)
  2 件のコメント
Joan Vazquez
Joan Vazquez 2020 年 9 月 1 日
Lovely.
Matlab's marketing department needs to popularize a proper adjective :P
Ben
Ben 2024 年 4 月 18 日 12:56
After seeing many arrayfuns/loops/etc. used as solutions for similar questions on this site, along with getting them suggested by LLM chat bots, this solution is just so satisfying
*feels good meme*

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