フィルターのクリア

Polar to cartesian conversion problem

3 ビュー (過去 30 日間)
Michael Elman
Michael Elman 2020 年 8 月 31 日
コメント済み: Michael Elman 2020 年 8 月 31 日
Hey,
I need to convert two vectors in polar coordinates (rho,phi) to cartesian coordinates, but something goes wrong because if I convert it back (from cartesian to polar) I don't get the same results ().
phi=linspace(0,2*pi,N);
rho=linspace(0,R_a,N);
[x,y] = pol2cart(phi,ro);
[theta2,rho2] = cart2pol(x,y);
Thanks in advance.

採用された回答

Stephen23
Stephen23 2020 年 8 月 31 日
編集済み: Stephen23 2020 年 8 月 31 日
"but something goes wrong because if I convert it back (from cartesian to polar) I don't get the same results"
Nothing goes wrong, you just have two different representations of the same angle.
Your input angles are given over the range 0 .. 2*pi, but cart2pol documentation clearly states that its ouput "...value of the angle is in the range [-pi pi]", so we would certainly not expect to have the same values.
You can convert to 0..2*pi using mod:
theta2 = mod(theta2,2*pi);
Note that due to floating point error we would still not expect those values to be exactly the same, but close enough.
  1 件のコメント
Michael Elman
Michael Elman 2020 年 8 月 31 日
Thank you!

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeArray Geometries and Analysis についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by