How do i multiply 2 increasing variables
1 回表示 (過去 30 日間)
古いコメントを表示
Hello everyone i was wondering if u could help me multiply these two increasing variables. They just do not multiply correctly
v0 = (10:1:20);
theta = (30:1:40);
v0_x = v0.*cosd(theta);
v0_y = v0.*sind(theta);
6 件のコメント
Sara Boznik
2020 年 8 月 14 日
for v0 = 10:1:20;
for theta = 30:1:40;
v0_x = v0.*cosd(theta)
v0_y = v0.*sind(theta)
end
end
Do you need this?
採用された回答
Shae Morgan
2020 年 8 月 14 日
編集済み: Shae Morgan
2020 年 8 月 14 日
Is this more what you were looking for?
v0 = (10:1:20);
theta = (30:1:40);
for i= 1:length(v0)
for j = 1:length(theta)
v0_x(i,j)=v0(i)*cosd(theta(j));
v0_y(i,j)=v0(i)*sind(theta(j));
end
end
v0_x
v0_y
4 件のコメント
Shae Morgan
2020 年 8 月 14 日
meshgrid() is another great solution here
x=[1 2 3]; %x array
y=[3 2 1]; %y array
[X,Y]=meshgrid(x,y)
%X is a length(y) long set rows of x
%Y is a length(x) long set of columns of y
using these matrices with the point multiplication will give the same outcome. The for-loops feel more intuitive and are visually understandable as you read through the code, but meshgrid requires fewer lines and a little more understanding of what it's doing.
In the end it's preference. I prefer code readability (or familiarizing yourself with new functions so you can improve readability!)
その他の回答 (1 件)
Bruno Luong
2020 年 8 月 14 日
編集済み: Bruno Luong
2020 年 8 月 14 日
v0 = (10:1:20);
theta = (30:1:40);
v0_x = v0.*cosd(theta.'); % horizontal .* vertical vectors
v0_y = v0.*sind(theta.');
0 件のコメント
参考
カテゴリ
Help Center および File Exchange で Logical についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!