String scalar or character vector must have valid interpreter syntax

Rx(1)= "(cos(seta)-0.3 * sin(seta)) * Rx_" ;

Ry(1)= "(0.3*cos(seta) + sin(seta)) * Ry_";

there are my variable and

I wrote the plot title like this

title(Rx(1)+" + "+Ry(1));

but I recieve this error message,' String scalar or character vector must have valid

interpreter syntax' . How can I fix it?

Answer 1

[Adam Danz]

You probably want something like

title(sprintf('%.2f + %.2f', Rs(1), Ry(1)))

See sprintf for more info.

Update

Set interpretter to 'none',

title(Rx(1)+" + "+Ry(1),'Interpreter','none');

[Gookki Jeong]

no,,, I just want like this, and It works actually, however I get warning error massage also. I don't know why I get warning...

[Adam Danz]

I didn't see that the Rx and Ry values had quotes. In the furture, it would be helpful if you format your code using the [>] button in the question/comment editor.

I've updated my answer with the solution.

[Walter Roberson]

Interpreter none, or use \_