MATLAB Answers

replacing Nan with 0

89 ビュー (過去 30 日間)
Caroline Prekker
Caroline Prekker 2020 年 7 月 25 日
編集済み: madhan ravi 2020 年 7 月 26 日
I have an excel file that I need to replace nan with zeros
I am using this piece of code and am getting error : Array indices must be positive integers or logical values
Error in "isnan(auPoints(r,c)) = 0;
I am not sure how to fix it or what I am doing wrong
for r = 4:1:22
for c = 2:1:29
if isnan(auPoints(r,c))

回答 (3 件)

Star Strider
Star Strider 2020 年 7 月 25 日
Try this:
auPoints - fillmissing(auPoints, 'constant',0);
It might be advisable to save the output to a different variable, in order to preserve the original ‘auPoints’ matrix.
See the documentation for fillmissing (R2016b and later versions) for details.

madhan ravi
madhan ravi 2020 年 7 月 25 日
編集済み: madhan ravi 2020 年 7 月 25 日
auPoints(isnan(auPoints(r, c))) = 0
  2 件のコメント
madhan ravi
madhan ravi 2020 年 7 月 25 日
Well it’s assumed that c was within the bounds.
Try this: (OBSCURE)
auPoints = subsasgn(auPoints, substruct('()', {isnan(auPoints)}), 0)


jonas 2020 年 7 月 25 日
The line does not work because the left part just returns a logical.
isnan(auPoints(r,c)) = 0
It is similar to writing
isnan(NaN) = 0
...which makes no sense but returns the same error message
For this type of basic operation it is better to make use of logical indexing. For example, if you want to replace all your NaNs with zeros, you can write the following
mask = isnan(auPoints);
auPoints(mask) = 0;
The first line returns a logical array (1's and 0's) with the same size as the original array. This array is then used to index the original array. Faster and easier than loops.
More about logical indexing and indexing in general here.
  2 件のコメント
jonas 2020 年 7 月 25 日
I don't see how that is possible. The variable mask is literally defined in the first out of the two lines.
Still, you could try the following:
auPoints(isnan(auPoints)) = 0
Note that this is exactly the same, just reduced to one line



Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by