Replacing Values in Matrix with NaN's based on Row and Column

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Michelle De Luna
Michelle De Luna 2020 年 6 月 24 日
コメント済み: Michelle De Luna 2020 年 6 月 24 日
Hi everyone!
I hope all of you are well. I'm currently working on replacing specific element values with NaN's within a matrix that is 300x600. I want to replace the values based on pairs of rows and columns that I have previously identified. I'm unsure if I would use a for loop or if I would have to create a mask or if there is a simpler way of approaching the problem, but any help would be greatly appreciated! Thank you in advance! :)
M.

採用された回答

madhan ravi
madhan ravi 2020 年 6 月 24 日
編集済み: madhan ravi 2020 年 6 月 24 日
matrix(ismember(matrix, [3,7,1])) = nan % an example of replacing numbers 3,7 & 9 with nans
% or
matrix = rand(5); % an example
rows = [2, 5];
columns = [1, 4];
idx = rows + (columns - 1) * size(matrix, 1);
matrix(idx) = nan

その他の回答 (1 件)

Tommy
Tommy 2020 年 6 月 24 日
Possibly, you could use sub2ind() to convert your rows and columns to linear indices:
ind = sub2ind(size(yourMatrix), yourRows, yourCols);
yourMatrix(ind) = NaN;
  1 件のコメント
Michelle De Luna
Michelle De Luna 2020 年 6 月 24 日
Tommy, thank you for your speedy response! I've accepted the second response but appreciate your help.

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