A complicated matrix manipulation
1 回表示 (過去 30 日間)
古いコメントを表示
So I have a matrix, let's say
A = [1 2;
1 0;
3 2;
0 1;
2 1;
1 2];
[r,c] = size(A);
In general, what I would like to do is:
for i = 1:r-1
x = A(6,1)*A(i,1) + A(6,2)*A(i,2);
end
However, here is the issue: if A(i,1) and/or A(i,2) is zero, and let's assume just A(i,1) is 0 and A(i,2) is non-zero, then, instead I would like to do:
x = A(6,1)*A(i-1,1) + A(6,2)*A(i,2);
And in case, even A(i-1,1) is also zero, then, I would like to do:
x = A(6,1)*A(i-2,1) + A(6,2)*A(i,2);
and so on and so forth (same for A(i,2)). Note, A(1,1), A(1,2), A(6,1), A(6,2) are always non-zeros. I am trying to get my head around it, but so far no luck, although it seems it should have a simple and efficient way.
Your help is highly appreciated. Please let me know if anything seems confusing.
Thanks in advance!
2 件のコメント
Stephen23
2020 年 6 月 19 日
Your example matrix only has five rows, so none of your example code accessing its (non-existent) sixth row will work.
採用された回答
Stephen23
2020 年 6 月 19 日
編集済み: Stephen23
2020 年 6 月 19 日
Try this reasonably "simple and efficient way":
r = size(A,1);
x = nan(r,1);
for k = 1:r
r1 = find(A(1:k,1),1,'last');
r2 = find(A(1:k,2),1,'last');
x(k) = A(6,1).*A(r1,1) + A(6,2).*A(r2,2);
end
3 件のコメント
Stephen23
2020 年 6 月 19 日
編集済み: Stephen23
2020 年 6 月 19 日
'...generalizing it for "n" number of columns of A'
C = cumsum(A(:)~=0,1); % requires that first and last rows do not contain zeros!
B = nonzeros(A);
B = reshape(B(C),size(A));
x = sum(A(6,:).*B,2)
Personally I would just use a loop, as it makes the code intent much clearer.
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Number Theory についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!