Solving matrices in form of (A + Bx = C)?

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Keith Grey
Keith Grey 2020 年 6 月 15 日
回答済み: Shivang Srivastava 2020 年 6 月 19 日
% How do I write to solve for y?
A = [1 2; 3 4];
B = [0 0; 1 1];
y = [x1; x2];
C = [1; 0];
% y should be a 2x1, but I'm getting a 2x2.
  2 件のコメント
Ameer Hamza
Ameer Hamza 2020 年 6 月 15 日
Is the equation correct? A is 2x2, B is 2x2, and y is 2x1. A cannot be added to B*x.
madhan ravi
madhan ravi 2020 年 6 月 15 日
Exactly I second Ameer’s comment.

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Shivang Srivastava
Shivang Srivastava 2020 年 6 月 19 日
As per my understanding of your code, in the equation A + Bx = C:
Matrix A is of size 2 * 2
Matrix B is of size 2 * 2
Matric C is of size 2 * 1
So when you are trying to perform the operations because of size mismatch of A, C & B*y your answer is evaluated to be a 2*2 matrix.
You can check the following code snippet for a better understanding of this:
A = [1 2; 3 4];
B = [0 0; 1 1];
C = [1; 0];
y = (C - A)\B
If you still face any difficulty you can refer to the following documentations:

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