How to calculate derivative of function of inside of another function ?

I can calculate g(-2) but I can not calculate g'(-2) at the same time with g(2). How can I write a function to calculate both of them in one function.

Answer 1

[madhan ravi]

doc syms
doc diff

[Hasan Berke Bankoglu]

In .m file, I wrote this code snippet below. I could get result of g1(-2) but I couldn't get result of g3 which is derivative of g1. How can I get that result?

function g = g1(x)

g1 = (x.^2).*(exp(x*-1))

function h = g3(x)

syms x

g3 = diff(g1(x))

fprint(g3)

end

end

[madhan ravi]

syms x
g(x) = x^2*exp(-x);
gdot(g) 

function gdot_val = gdot(g)

gdot_val(x) = diff(g);
gdot_val = gdot_val(-2);
end

[madhan ravi]

You need to figure out to encapsulate because its your homework not mine.

[Hasan Berke Bankoglu]

Yes, it's mine and it's my responsibility and I want to learn it completely. I couldn't understand your code snippet. Can you tell me what the wrong things are in my codes? Just tell me what the wrong, I don't want any code. If I can learn what the wrong, then, I may solve it.

[madhan ravi]

• You create a function
• Which takes in a function
• You evaluate it at a given point
• You differentiate that function at a given point (Hint: diff(...) )

Possible sources:

doc syms 
doc diff 
doc function

Lots of examples to go with the flow.