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Avoid +0 when using fprintf %+d

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giannit
giannit 2020 年 6 月 1 日
コメント済み: giannit 2020 年 6 月 1 日
Consider the code
names={'aba','cda','efa','fea','pod'};
numbers=randi([-1 1],5,4);
for i=1:5
fprintf('|%s|%+d|%+d|%+d|%+d|\n',names{i},numbers(i,:))
end
whose output is similar to
|aba|+0|+1|+1|+1|
|cda|-1|+1|-1|+1|
|efa|+1|+0|-1|-1|
|fea|+1|+0|-1|+1|
|pod|+1|-1|-1|-1|
Is there a way to remove the plus in front of the 0s, or to not print + when the number is 0?

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dpb
dpb 2020 年 6 月 1 日
編集済み: dpb 2020 年 6 月 1 日
Not w/o some code logic of one form or the other, no. There is no "magic bullet" format descriptor that behaves as desired; as you notice, the '+' adds the sign to any numeric field. There also is no conditional formatting expression built in like an Excel format expression.
You could, however, build the format string dynamically and insert the plus only where the values aren't zero. Or, (in a somewhat less elegant solution imo) you could write the output string to a variable first and then do character substitution on it before displaying or writing to file or whatever it is that is the end objective.
The latter is, of course, a trivial change to implement even if somewhat klunky--
for i=1:5
str=sprintf('|%s|%+d|%+d|%+d|%+d|\n',names{i},numbers(i,:));
fprintf('%s\n',strrep(str,'+0',' 0'))
end
Let's see on the former...scratch, stratch...emmm....ah! OK, here, try this:
>> fmts={'% d|','%+d|'};
>> disp(cell2mat([compose('|%s|',string(names.')) compose(fmts((numbers~=0)+1),numbers)]))
|aba|+1|+1|-1|+1|
|cda|-1|+1| 0| 0|
|efa|+1|-1| 0|+1|
|fea|-1| 0|-1| 0|
|pod|+1| 0| 0|-1|
>>
  1 件のコメント
giannit
giannit 2020 年 6 月 1 日
Thank you for both solutions!

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