Create a vector with for loop with mathematical operations

3 ビュー (過去 30 日間)
Hasan Berke Bankoglu
Hasan Berke Bankoglu 2020 年 5 月 10 日
コメント済み: Stephen23 2022 年 1 月 23 日
w=[5 4 3 2]
Use this vector in a mathematical expression to create the following vectors:
My code snippet is below, code for that question. When I run it, I can't get expected result. I just want to create a vector as noted above.How can I solve that question?
w=[5 4 3 2]
for i= w
a3=[1/(i+i)]
b3 =[i^i]
c3 =[i/sqrt(i)]
d3 =[(i^2)/(i^i)]
end

採用された回答

KSSV
KSSV 2020 年 5 月 10 日
Read about ., element by element operations.
w = [5 4 3 2] ;
a = 1./(w+w) ;
b = w.^w ;
c = w./sqrt(w) ;
d = w.^2./w.^w ;

その他の回答 (1 件)

Toder
Toder 2020 年 5 月 10 日
To fix your current code, you need to use indices in the for loop.
w=[5 4 3 2]
for i = w
a3(6-i)=[1/(i+i)]
b3(6-i) =[i^i]
c3(6-i) =[i/sqrt(i)]
d3(6-i) =[(i^2)/(i^i)]
end
This assigns a3(1) in the first loop, a3(2) in the second, etc. Your code reassigns the scalar a3 each loop. The indices I use are somewhat strange because we're looping over w, which is fine, it just makes indices harder to keep track of. You could do it differently by using a counter:
w=[5 4 3 2]
j = 1
for i = w
a3(j)=[1/(i+i)]
b3(j) =[i^i]
c3(j) =[i/sqrt(i)]
d3(j) =[(i^2)/(i^i)]
j = j+1
end
Or you could have your for loop count from 1 to 4:
w=[5 4 3 2]
for i = 1:4
a3(i)=[1/(w(i)+w(i))]
b3(i) =[w(i)^w(i)]
c3(i) =[w(i)/sqrt(w(i))]
d3(i) =[(w(i)^2)/(w(i)^w(i))]
end
All this being said, I recommend "vectorizing" your code where possible. Dot operators perform arithmetic element-by-element, see the documentation for dot multiplication here. For instance, the whole a3 vector can be defined this way:
a3 = 1./(2*w)
  5 件のコメント
David Banahene
David Banahene 2022 年 1 月 23 日
I have a vector a=[1:5] and would want to know how to plot (a-3)^3.
Stephen23
Stephen23 2022 年 1 月 23 日
a = 1:5;
b = (a-3).^3;
plot(a,b)

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeLoops and Conditional Statements についてさらに検索

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by