How to speed up this code consisting of 6 nested FOR loops?

2 ビュー (過去 30 日間)
Tanguy
Tanguy 2012 年 10 月 29 日
Hi All,
I am trying to speed up the code below which consists of 6 nested FOR loops.
The purpose of this code is to fill a large, sparse matrix A with ones, and a large vector b with elements from a matrix dd of size TxTxN.
I have access to the Parallel Computing Toolbox, and ultimately this code will run on a cluster.
Any comments/suggestions would be greatly appreciated.
N= big number (e.g. 10000)
T=24;
A=sparse(N*T*(T+1)/2,(N-1)*T+T); %matrix to be filled
b=sparse(N*T*(T+1)/2,1); %vector to be filled
tempT = (T+1)*T/2; % constant used in the loop
for j=1:N
for t1=1:T
for t2=t1:T
for t3=1:t2-t1+1
rw = (j-1)*tempT + (t1-1)*(T-t1/2)+t2;
cl = (j-1)*T+t1-1+t3;
A(rw,cl) = 1;
for t4=t1:t2
for t5=t4:t2
b(rw) = b(rw) + dd(t4,t5,j); % dd is given, size(dd)=TxTxN
end
end
end
end
end
end
An earlier discussion on a simplified version of this with only 3 nested loops can be found here: http://www.mathworks.com/matlabcentral/answers/52005-how-to-transform-these-three-nested-for-loops-into-a-parfor-loop
  8 件のコメント
Tanguy
Tanguy 2012 年 10 月 29 日
編集済み: Tanguy 2012 年 10 月 30 日
The function of this code is to fill a sparse matrix A with ones, and a large vector b with elements from a matrix dd of size TxTxN.
Inputs: N, T, dd
Outputs: A, b
Any input would be appreciated, thanks!
Tanguy
Tanguy 2012 年 10 月 30 日
That's right TxTxN

サインインしてコメントする。

採用された回答

Matt J
Matt J 2012 年 10 月 30 日
編集済み: Matt J 2012 年 10 月 30 日
Here's one proposal,
N=1e4;
T=24;
%dd=rand(T,T,N); %fake
tempT = (T+1)*T/2;
[T1,T2,T3]=ndgrid(1:T,1:T,1:T);
idx = (T2>=T1) & (T3<=T2-T1+1);
T1=T1(idx);
T2=T2(idx);
T3=T3(idx);
nt=numel(T1);
%Make row/col data
RW=(T1-1).*(T-T1/2)+T2;
CL=T1-1+T3;
RW=bsxfun(@plus,RW,(0:N-1)*tempT);
CL=bsxfun(@plus,CL,(0:N-1)*T);
%For building b
Z=zeros(nt,T^2);
for ii=1:nt % A very small loop, no need to optimize
[T4,T5]=ndgrid(T1(ii):T2(ii),T1(ii):T2(ii));
idx=T5>=T4;
T4=T4(idx);
T5=T5(idx);
ind=sub2ind([T,T],T4,T5);
Z(ii,ind)=1;
end
ddd=Z*reshape(dd,[],N);
A=sparse(RW,CL,1, N*T*(T+1)/2,N*T);
b=sparse(RW(:),1,ddd(:),N*T*(T+1)/2,1);
  4 件のコメント
Matt J
Matt J 2012 年 11 月 1 日
The values I get for max(b1-b2) are tiny ones on the order of 1e-13. This is easily attributable to floating point precision issues. Remember, the two approaches are not adding up the numbers in the same order. Are you not getting similarly small values?
A stronger check is to look at the percent error, for which I also get tiny values:
>> percentError = full( sum(abs(b1-b2))/sum(abs(b1))*100 )
percentError =
2.5104e-14
Tanguy
Tanguy 2012 年 11 月 1 日
編集済み: Tanguy 2012 年 11 月 1 日
Thanks for your reply. Yes I get similarly small values, but this leads the optimization algorithm which takes b as an input to return a different solution (corresponding to the same value of the objective function though, so that's fine). That's why I was asking. Thanks for your input.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeNumber Theory についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by