# Number of sequences with 3 or more ascending numbers

3 ビュー (過去 30 日間)
Avish Sjavi 2020 年 4 月 6 日
コメント済み: Matt J 2020 年 4 月 6 日
Hello,
I have following problem:
I have to find number of sequences occuring in vector. Such sequence contains 3 or more numbers which are ascending
so, for examplet
v = [ 1 8 2 5 8 0 0 1 2 3 4 9]
in this vector, such sequence occurs 2 times: 2 5 8 AND 0 1 2 3 4 9.
I would like to have these sequences stored in separate vector.
So far i have tried this:
v = [ 1 8 2 5 8 0 0 1 2 3 4 9]
n_sequences=0
for k = 1:length(v)
if v(k)<v(k+1)<v(k+2)<v(k+3)
n_sequences= n_sequences + 1
end
end
However this doesnt work as I supposed. I am not sure how to incorporate "3 OR MORE" into code.
Thanks,

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### 回答 (2 件)

Matt J 2020 年 4 月 6 日
all( diff(v(k:k+2)) >= 0 )
##### 2 件のコメント表示非表示 1 件の古いコメント
Matt J 2020 年 4 月 6 日
It tests whether you have 3 increasing elements in a row, as you asked for. Examples:
>> v = [ 1 8 2 5 8 0 0 1 2 3 4 9]
v =
1 8 2 5 8 0 0 1 2 3 4 9
>> k=3;
>> all( diff(v(k:k+2)) >= 0 )
ans =
logical
1
>> k=4;
>> all( diff(v(k:k+2)) >= 0 )
ans =
logical
0
>> k=6;
>> all( diff(v(k:k+2)) >= 0 )
ans =
logical
1

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Andrei Bobrov 2020 年 4 月 6 日
lo = diff(v) > 0;
lo = [~lo(1);lo];
lo2 = [lo(2:end);false]|lo;
i = cumsum(lo == 0 & lo2).*lo2;
j = accumarray(i + 1,1);
C = accumarray(i + 1,(1:numel(v))',[],@(x){v(x)});
out = C(J >= 3);

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