ASCII coding to get corresponding character
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I wrote this code so far, and I am getting the corresponding characters, except I get them all from 32 through 126, no matter what number I type in. Essentially I want to be able to type in a number between 32:126 and get only that numbers character. I want it to be if the code is less than 32 or more than 126 (aka out of that range) the user gets a "?" as an answer. And then the code answers "Bye!" when the -1 is inputed, since it is used to quit. Could I have some help adjusting this code to do that. Thank you!
character=input ('Enter ASCII code(s) or -1 to quit', 's')
n=32:126; %ASCII codes
for i=1:length(n)
fprintf('%c=%3d\n',n(i),n(i));
if input<32
output=?
if input>126
output=?
if input=-1
output='Bye!'
end
end
end
end
回答 (1 件)
input is a scalar, integer value (not to be confused with the input() function).
if input < 32 || input > 126
output = '?';
elseif input == -1
output = 'Bye!';
else
output = char(input);
end
16 件のコメント
Charlotte Reed
2020 年 3 月 19 日
In my answer, integer is a numeric scalar value (a single, numberic value). For example, input = 99.
If you're using the input function, change that variable name because Matlab will think that you're using the input function.
Do you intend to enter a vector of values or a single numeric value?
Charlotte Reed
2020 年 3 月 19 日
Adam Danz
2020 年 3 月 19 日
You won't change the input function. You'll change the variable name "input" from my answer. You can change it to any variable name such as inputNumber.
Charlotte Reed
2020 年 3 月 19 日
Charlotte Reed
2020 年 3 月 19 日
"It's still not working,"
Are you getting an error? An unexpected output?
Screenshots aren't that helpful because I can't copy/paste your code.
Also, why is n = 32:126 in there? And why the loop?
Take a few minutes and read the code. Look what it's doing. Make sense of it before running it. It's only a few lines of code. It seems like you're just copy/pasting without thinking about it.
Charlotte Reed
2020 年 3 月 19 日
Adam Danz
2020 年 3 月 19 日
My bet is that you have a variable in the workspace named input. Remove it.
clear('input')
Charlotte Reed
2020 年 3 月 19 日
BobH
2020 年 3 月 19 日
Merging Charlotte's code and Adam's answer to remove the variable which shares a name with function
userinput = input('Enter ASCII code or -1 to quit ');
if userinput < 32 || userinput > 126
output = '?';
elseif userinput == -1
output = 'Bye!';
else
output = char(userinput);
end
Charlotte Reed
2020 年 3 月 19 日
Adam Danz
2020 年 3 月 19 日
Charlotte Reed
2020 年 3 月 19 日
Walter Roberson
2020 年 3 月 19 日
clear input
You have a left-over variable named input
See my comment here that suggests to clear the input variable in addition to Walter's comment above.
Please take time to read and think about the code.
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