Hello everyone,
I have created a struct S as:
syms x1 x2 nnX1 nnX2
p1Space = linspace(0,50,10);
p2Space = linspace(0,25,10);
for i=1:10
S(i) = vpasolve(x1^2 + x2^2 - p1Space(i) == 0, x1*x2 - p2Space(i) == 0, [x1 x2]);
end
and I get an error when I perfom the following for loop in order to store specific elements into two arrays (XX1 and XX2):
for k = 1:10
XX1(k) = S(k).x1(2,1);
XX2(k) = S(k).x2(2,l);
end
When I type in the command window for example S(4).x1(2,1), the number appears on the screen, but inside the for-loop, this doesn't work. Any ideas why is this happening and how can I store these spesific values into the XX1 and XX2 arrays?
Thank you

1 件のコメント

Ameer Hamza
Ameer Hamza 2020 年 3 月 18 日
You are getting this error because S(1).x1 does not have two elements. Similar is the case for S(1).x2. All the other elements of S have two elements, therefore S(4).x1(2,1) in the command window. Try S(1).x1(2,1) in the command window.

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 採用された回答

Adam Danz
Adam Danz 2020 年 3 月 18 日
編集済み: Adam Danz 2020 年 3 月 18 日

1 投票

As stated in the documentation, the size of the vpasolve output corresponds to the number of the solutions. On the first iteration, there is only 1 solution which can be seen here,
S(1)
ans =
struct with fields:
x1: [1×1 sym]
x2: [1×1 sym]
On the first iteration of the k-loop (k=1), you're getting the error because you're trying to get the 2nd row of x1 and x2 but they only have 1 row.

その他の回答 (1 件)

Konstantinos Andrikos
Konstantinos Andrikos 2020 年 3 月 18 日

0 投票

Thank you for your responses. Problem solved!

1 件のコメント

Adam Danz
Adam Danz 2020 年 3 月 18 日
編集済み: Adam Danz 2020 年 3 月 18 日
Glad I could help.

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