Error using min. Matrix dimensions must agree.

Hello,

Perhaps this is a silly question, but I found no suitable answer. I'm having trouble using the 'all' syntax in min/max functions, I have MATLAB R2019a (this shoukd work for 2018b and above).

After having trouble with it, I decided to check it on a simpler matrix. Simply using min/max works as expected. But the following confuses me

Why do the matrix dimensions need to agree? According to the documentation, the 'all' option is to be applied on a single matrix. Furthermore, shouldn't the "1" I wrote be attributed to the dimension along which I want to find the mean? (should give me a 1x4 vector)

Thanks,

Gaby

[Stephen23]

"...but I found no suitable answer."

The documentation explains this, and has examples too.

"According to the documentation, the 'all' option is to be applied on a single matrix."

The max documentation also clearly shows the the dimension / "all" option is the third input argument (not the second input argument like you are doing).

[Gavriel Fleurov]

Got it, thanks!

Answer 1

[the cyclist]

You just need to be a bit more careful with the syntax. Take a look at the documentation.

max(rand(4),[],'all')

With the syntax you used, MATLAB is trying to interpret that as the two-input version

max(A,B)

where it tries to determine whether A or B has the larger elements.

[Gavriel Fleurov]

Got it, thanks!