Image Series Analysis: Curve fitting the pixels

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Avigdor
Avigdor 2012 年 10 月 14 日
Hi,
I have a series of k images of dimension m by n. The intensity of the each pixels in the image changes as a function of image number. I would like to fit each pixel in the series of k images to a simple function, but I do not know how to set up the loop.
How can I generate a pixel by pixel curve fit for the image series, and then display the results of the fit as a "map" of the fit values?
Thanks
  5 件のコメント
Avigdor
Avigdor 2012 年 10 月 15 日
No, it is much simpler than you imagine.
I am fitting the time course of the pixels to a simple exponential function, for a given change in parameter I apply to each image.
I need the fit parameters for each pixel to then map the parameters over a reference image.
Thanks.
Matt J
Matt J 2012 年 10 月 15 日
編集済み: Matt J 2012 年 10 月 15 日
What's wrong with the approach I already outlined for you? Extract the data for each pixel, curve fit that data, then replace the data with the fitted curve.

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回答 (1 件)

Matt J
Matt J 2012 年 10 月 14 日
編集済み: Matt J 2012 年 10 月 14 日
If you have the image series as an m x n x k array A, then you can extract the data for each m,n by
for m=1:M
for n=1:N
data=reshape( A(m,n,:) , 1,[]);
end
end
I'm not saying that's the optimal thing to do, but if you must use a loop, that's how you could do it. The optimal approach would depend on the form of the curve your fitting with.
  2 件のコメント
Avigdor
Avigdor 2012 年 10 月 14 日
Thanks for the tip! Yes, this would be the first step, but it isn't so much arranging the data that is the problem for me, it's the looping over the data to perform the fit.
Once you have generated data, how would you go about looping to perform the fit for each m over k and each n over k, then mapping to the image?
Matt J
Matt J 2012 年 10 月 14 日
編集済み: Matt J 2012 年 10 月 14 日
You would/could use the same loop you use to extract the data, but store the fitted curve to another matrix B
for m=1:M
for n=1:N
data=reshape( A(m,n,:) , 1,[]);
B(m,n,:)=reshape( mycurvefitFunction(data) ,1,1,[]);
end
end

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