Find minimum of a 15x100 and return in a vector of 1x100. is this possible?

I have

i=5 ; nu=150 ;
for j =1:15
    load(['output/GC/rank_', int2str(i), '/nu_',int2str(nu),'/NeNMF_GC_', int2str(j), '.mat'], ...
    'RRE_AS_V' );
     newAS (j,:)= (RRE_AS_V);
end

The variable newAS is 15 x 101 in size. if i do a median it works fine. It returns a 1x101

Median_newAS = median(newAS,1); 
    

However wheni do for min and max it appears the values are swapped when i write to a table

% however for min and max 
Min_newAS = min(newAS); 
Max_newAS = max(newAS); 

I write to a table. but when i examin my min values they look like they are rather the max values. and max values are small

T_AS=table(Min_newAS',Max_newAS',Max_newAS' ,'VariableNames',{'Min_AS','Med_AS','Max_AS'});      
namedatfile= ['r_' int2str(i),'_nu_' int2str(nu) '_pass.dat'];
fname = namedatfile;
writetable(T_AS,fname,'Delimiter',' ')

Answer 1

[Matt J]

The names of the variables you wrote to the table

Min_AS,Med_AS,Max_AS

are different from the original variable names you showed us,

Median_newAS
Min_newAS 
Max_newAS 

So, it wouldn't be a surprise if the data you wrote to the table was different from what you computed.

[fadams18]

Sorry actually they are the same i just wanted to simplify the code here for potential solvers. I have edited the question

[Matt J]

I suggest you attach newAS in a .mat file, so we can try to reproduce what you see.