i have a matrix:
3 0
1 2
1 4
i can find the smallest element in 1st column i.e. 1 & 0 in the second column.
I need to assign a variable as 0 for each multiple similar element in a single column i.e 1 & 1 in the 1st column & assign 1 to only one unique element in single column i.e 0 in 2nd column.

3 件のコメント

Adam Danz
Adam Danz 2019 年 12 月 13 日
編集済み: Adam Danz 2019 年 12 月 13 日
What do you mean by assigning a value? To what? Could you provide an example of the expected output? I'm assuming you're referring to graph transversal but I can't quite picture the final output.
anshuman mishra
anshuman mishra 2019 年 12 月 13 日
編集済み: anshuman mishra 2019 年 12 月 13 日
i mean to say lets take a variable v.
Then required answer would be v =0 1 ( 0 as in multiple similar element in a single column i.e 1 & 1 in the 1st column & 1 to only one unique element in single column i.e 0 in 2nd column.
anshuman mishra
anshuman mishra 2019 年 12 月 13 日
Sorry i typed traversal instead of element. My bad :)

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 採用された回答

Fangjun Jiang
Fangjun Jiang 2019 年 12 月 13 日

0 投票

V=[3 0;1 2;1 4];
out=sum(M==min(M))==1

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