Hi !!! Have a nice day.
I have a code that starts with the generation of a matrix A,
after a numerical process at the end I have a matrix B
A = [a, b, c,… ..
q, w, r,….];
instructions
instructions
instructions
instructions
instructions
instructions
B = [d, e, f,….
and, u, I, ...];
At the end of the numerical process I have matrix B, immediately
the values of B are assigned to A in this way
A = B
What instruction I need to do to generate this cycle N times, that this; the results of B introduce them to input A?
I hope you understand what I want to do
Thank you

6 件のコメント

Raj
Raj 2019 年 12 月 5 日
"cycle N times" - A for loop maybe? Try giving more clarity!
Ricardo Gutierrez
Ricardo Gutierrez 2019 年 12 月 5 日
I already tried it with a "for" cycle but only when N = 1 the matrix A is updated with values of matrix B.
When N => 1 say N = 5 the values are repeated 4 times, it is only updated the first time.
Adam Danz
Adam Danz 2019 年 12 月 5 日
The question is unclear. Do you want to concatenate A n-times? Horizontally or vertically?
If you provide a pair of inputs and expected outputs it may be helpful to explain the problem.
Ricardo Gutierrez
Ricardo Gutierrez 2019 年 12 月 5 日
No, I don't want to concatenate. I want to update the values of A with the resulting matrix B, in each cycle(n times). But this I have not been able to achieve.
Adam Danz
Adam Danz 2019 年 12 月 5 日
編集済み: Adam Danz 2019 年 12 月 5 日
" I want to update the values of A with the resulting matrix B"
So you want to completely overwrite A with whatever is stored in B on each iteration.
But this I have not been able to achieve"
Why not? What specific problems have you faced?
Again, a simple example of expected input and outputs usually saves quite a bit of time and dialog.
Ricardo Gutierrez
Ricardo Gutierrez 2019 年 12 月 5 日
You are right.
I should check my code.
Thank you very much for your patience and your help.

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 採用された回答

meghannmarie
meghannmarie 2019 年 12 月 5 日

0 投票

Can you show your code? Make sure you are initally setting A before the for loop. If I am understanding the problem, it should look something like this:
A = [a,b,c;q,w,r];
for n = 1:5
% instructions
% instructions
% instructions
B = [d,e,f;l,m,n]
A = B;
end

5 件のコメント

Ricardo Gutierrez
Ricardo Gutierrez 2019 年 12 月 5 日
Hello good day
Thanks for your attention
Yes, this is the structure of the code as you show it.
Matrix A updates me only in the first cycle, but in subsequent cycles it repeats the first update.
The code I am working on has 210 lines is very extensive
Adam Danz
Adam Danz 2019 年 12 月 5 日
If you expect to vertically concatenate A,
B = [d,e,f;l,m,n]
A = [A;B];
If you expect to horizontally concatenate A,
B = [d,e,f;l,m,n]
A = [A,B];
Ricardo Gutierrez
Ricardo Gutierrez 2019 年 12 月 5 日
No, I don't want to concatenate. I want to update the values of A with the resulting matrix B, in each cycle. But this I have not been able to achieve.
meghannmarie
meghannmarie 2019 年 12 月 5 日
Is variable A part of the input into building variable B? There must be an error in your code, I do not know how to troubleshoot without code.
Ricardo Gutierrez
Ricardo Gutierrez 2019 年 12 月 5 日
Thank you very much.
You are right there must be some error in my code.
Thank you for your patience and attention.

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