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Filling missing elements in a matrix.

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Sridutt Gokul
Sridutt Gokul 2019 年 12 月 3 日
コメント済み: Adam Danz 2019 年 12 月 3 日
Hello,
I have a matrix like this:
A = [1 0 2 0 0 2 2 2 0 2 2 2 [] [] [] [] [] ;
0 3 2 1 0 1 2 0 1 0 0 0 [] [] [] [] [] ;
0 2 3 0 2 0 1 3 0 0 0 0 [] [] [] [] [] ;
0 0 2 2 0 1 1 0 2 0 0 0 [] [] [] [] [] ;
3 0 3 0 0 0 0 1 0 1 0 1 [] [] [] [] [] ;
4 0 4 0 0 1 1 0 0 0 0 1 0 [] [] [] [] ;
0 0 3 0 0 0 0 0 0 0 0 0 0 [] [] [] [] ;
0 0 2 3 0 0 0 0 0 0 0 0 0 2 [] [] [] ;
0 0 0 3 0 1 0 0 0 0 0 [] 1 0 [] [] [] ;
4 0 0 0 3 3 1 0 0 [] 0 [] 0 0 [] 0 0 ;
0 0 0 0 2 5 1 0 0 0 0 0 0 0 [] 0 0 ;
0 0 0 0 0 1 0 0 0 0 0 0 0 0 [] 0 0 ;
0 0 2 [] 1 3 0 0 0 0 0 0 0 0 [] 0 0 ;
2 2 2 3 0 0 0 0 0 0 0 0 0 0 [] 0 0 ;
0 1 1 2 1 0 [] 0 [] 0 [] 0 [] 0 [] 0 0 ;
0 0 0 [] 0 0 0 [] 0 [] 0 [] [] 0 [] 0 0 ;
1 0 1 [] 0 0 0 0 [] 0 [] 0 [] 0 [] 0 0 ;
0 1 0 0 0 0 0 [] 0 [] 0 [] [] 0 [] 0 0 ;
[] 3 0 1 0 0 [] 0 [] 0 [] 0 0 0 [] 0 [] ;
[] [] [] [] 0 0 0 [] 0 [] 0 [] 0 0 [] 0 [] ;
[] [] [] [] 0 [] [] [] [] [] [] [] [] [] [] [] [] ;
[] [] [] 0 [] 0 0 0 [] 0 [] 0 0 0 0 [] [] ;
[] [] [] [] [] 0 0 [] 0 [] 0 [] 0 0 0 [] [] ;
[] [] [] [] 0 0 [] 0 [] 0 [] 0 0 0 [] [] [] ];
The [] denote missing elements. I want to fill in all the missing elements by holding the previous value in the same row (value to the left of the missing element) and in cases where the row begins with [] it should fill in the values from the right, again in the same row.
Please help me, I've tried the fillmissing function but it does not produce the results I am looking for.
Thanks in advance.
  1 件のコメント
Adam Danz
Adam Danz 2019 年 12 月 3 日
編集済み: Adam Danz 2019 年 12 月 3 日
That doesn't describe your real variable 'A'. In your description, A is a matrix but matrices cannot have empty values. They can have NaN values, but not empty values.
I'm guessing A is actually a cell array of scalar values that looks like this (execute this in the command window and please confirm this assumption).
A = num2cell(randi(9,20,10)); % random integers
A(randi(numel(A),1,100)) = {[]}; % remove 100 values and replace with empty
Also, what if the preceeding value (or the next value) is also empty?

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Adam Danz
Adam Danz 2019 年 12 月 3 日
編集済み: Adam Danz 2019 年 12 月 3 日
Use F = fillmissing(A,method); requires >=r2016b
Here's a demo
% Create a 20x10 cell array of integer values
% and replace 100 of the values with empties
A = num2cell(randi(9,20,10));
A(randi(numel(A),1,100)) = {[]};
% Fill empties with NaNs
A(cellfun(@isempty,A)) = {NaN};
% Convert to matrix and replace all empties with
% previous value except rows that lead with empty
F = fillmissing(cell2mat(A).','previous').';
% Replace the leftover rows the lead with empties
F = fillmissing(F.','next').';
Alternatively you could try this but in my quick tests, it didn't work so well
F = fillmissing(cell2mat(A).','previous','EndValues','next').';
If you need to convert the matrix back to a cell array (not recommended)
C = num2cell(F);
  2 件のコメント
Sridutt Gokul
Sridutt Gokul 2019 年 12 月 3 日
Thank you, this is what I needed.
Adam Danz
Adam Danz 2019 年 12 月 3 日
Glad I could help!

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