How to compare betwen two cells?

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Mira le
Mira le 2019 年 11 月 19 日
コメント済み: Ridwan Alam 2019 年 11 月 22 日
How to compare betwen two cells? like this:
S and T1 are two cell with different values:
c=1:
i=1;
SI{c},T1{i}
the error "Cell contents reference from a non-cell array object." appear
what is the suitble command matlab to use?
  3 件のコメント
Mira le
Mira le 2019 年 11 月 19 日
編集済み: dpb 2019 年 11 月 19 日
S is cell intialised as
S= {1 2 , 2 3}
T1 also a cell
like
T1{1} = 1 2 3
T1{2} = 1 2 4
T1{4} = 1 2 3 5
S{1} = 1 2
S{2} = 2 3
each S{i} exist in T1{j}
dpb
dpb 2019 年 11 月 19 日
The above is simply not so as written--
>> S= {1 2 , 2 3}
S =
1×4 cell array
{[1.00]} {[2.00]} {[2.00]} {[3.00]}
>> whos S
Name Size Bytes Class Attributes
S 1x4 480 cell
>> S{1}
ans =
1.00
>> S{2}
ans =
2.00
>> T1{1} = 1 2 3
T1{2} = 1 2 4
T1{4} = 1 2 3 5
T1{1} = 1 2 3
Error: Unexpected MATLAB expression.
So the T1 can't be...could write something like:
>> T1{1} = [1 2 3]
T1 =
1×1 cell array
{1×3 double}
>> S{T1{1}}
ans =
1.00
ans =
2.00
ans =
2.00
>>
returns each element indexed into S but in a comma-separated list. This can be consolidated by surrounding with braces as:
>> [S{T1{1}}]
ans =
1.00 2.00 2.00
>>
Or, you can return the elements as cell array if don't dereference S but only T1:
>> S(T1{1})
ans =
1×3 cell array
{[1.00]} {[2.00]} {[2.00]}
>>
As requested before, we need to know precisely what storage form you do have; what you've posted simply doesn't work as written.
That's why asked for the output from the whos command--it shows what exists unequivocally.

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Ridwan Alam
Ridwan Alam 2019 年 11 月 19 日
編集済み: Ridwan Alam 2019 年 11 月 20 日
T1{1} = [1 2 3];
T1{2} = [1 2 4];
T1{4} = [1 2 3 5];
S{1} = [1 2];
S{2} = [2 3];
%
%
setdiff(cell2mat(T1),cell2mat(S))
% ans =
%
% 4 5
Please accept the answer if it works!
  1 件のコメント
Ridwan Alam
Ridwan Alam 2019 年 11 月 22 日
Hi Mira,
If this solution works, please accept as an answer.
If there is anything wrong, please let me know.
Thanks!!

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