Polyshape: stop Connecting first and last points.

Hello all, How you doin? Can you please help me with an issue?
Problem:
I have many sets of Data (Like attached one), in two vectors that are produced seperetly by another script.
Now, I need to plot them, devide them between "Closed" and "Open" , Then search between "Closed" ones to see which one is the stable one.
I used "polyshape" like it:
load('Data');
a = polyshape(Data(:,1),Data(:,2),'Simplify',true);
b =regions(a);
plot(b)
the problem is that polyshape connects first and last point automaticlly (even when simplify is off). So all regions are closed now and finding stable region encounter with wrong answers.
Do you have any idea, about disabling this feature (to leave the plot as it is), Or any alternative command that works like "polyshape" and has ability to recognize regions with their boundry points?
Thanks a lot for your time.
----------------------------------------------------------------------------------------------------
Another Example:
how to find boundries of JUST closed area of this points? (Data2.m)
ee.JPG

5 件のコメント

Adam Danz
Adam Danz 2019 年 11 月 12 日
How are you categorizing closed and open?
For open 'shapes' ('lines' is probably better), how do you expect that they appear? Why not just apply polyshape() to the closed sets and use plot() for the open ones?
Armin Mashhadi
Armin Mashhadi 2019 年 11 月 12 日
Hi,
I don't meant "how to plot (or show them). and above picture was just an example.
Exactly the problem is about how to categorize closed sets from open lines ( since "polyshape" connects first and last point, artificial closed areas have been created.)
Code's about to find closed sets, then search better one (for example which has stable points).
but i can't find closed regions at the first place :(
Adam Danz
Adam Danz 2019 年 11 月 12 日
編集済み: Adam Danz 2019 年 11 月 12 日
I see.
I don't think this is an easy problem to solve. How do you define what is open and what is closed? Are these open?
I think there should be a definition of what it means to be "open" before proceeding.
Adam Danz
Adam Danz 2019 年 11 月 13 日
Armin Mashhadi's answer moved here as a comment.
Got it.
Adam Danz
Adam Danz 2019 年 11 月 13 日
@ Armin Mashhadi, if you'd like to share your solution, please add it as an answer. "got it" isn't an answer.

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回答 (1 件)

Stijn Haenen
Stijn Haenen 2019 年 11 月 12 日

0 投票

Hi,
do you mean this?
load('Data');
a=polyshape(Data(:,1),Data(:,2));
b=regions(a);
area=[b(2,1).Vertices(:,1) b(2,1).Vertices(:,2)];
line=[b(3,1).Vertices(:,1) b(3,1).Vertices(:,2);b(1,1).Vertices(:,1) b(1,1).Vertices(:,2)];
shape_area=polyshape(area);
plot(regions(shape_area));
hold on
[c,d]=max(line(1:end-1,1)-line(2:end,1));
plot(line(d+1:end,1),line(d+1:end,2),'black');
plot(line(1:d-1,1),line(1:d-1,2),'black');

1 件のコメント

Armin Mashhadi
Armin Mashhadi 2019 年 11 月 12 日
Hi,
I really appreciate your efford and spending time.
But no, that was not wat i meant.
The question is how to find that region2 is closed and others are not , automaticlly.
But you assumed that region2 is closed then drew using its vertices.

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