Hi,
I am wonderinh whether I can write something like this:
If any(ismember(result , [" nafor", "kform", "acet"]))

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meghannmarie
meghannmarie 2019 年 10 月 3 日
編集済み: meghannmarie 2019 年 10 月 3 日

0 投票

if you are trying to match string to string, try this:
if any(contains([' nafor','kform','acet'],result))

5 件のコメント

Muazma Ali
Muazma Ali 2019 年 10 月 3 日
as I have written I am dealing with string vectors here, not single string.
The vector may contain one of the mentioned strings that the if statement has to investigate
meghannmarie
meghannmarie 2019 年 10 月 3 日
編集済み: meghannmarie 2019 年 10 月 3 日
Maybe I do not undertsand your question, this gives me a true answer for your if statement to investigate.
result = ["kform","acet","other"];
if any(contains({' nafor','kform','acet'},result))
...
end
Muazma Ali
Muazma Ali 2019 年 10 月 3 日
Thanks I understand it now.
Stephen23
Stephen23 2019 年 10 月 4 日
編集済み: Stephen23 2019 年 10 月 4 日
Note that [] is a concatenation operator, so this code:
[' nafor','kform','acet']
is just a complex way of writing this:
' naforkformacet'
Perhaps you actually intended to define strings, rather than character vectors?
Muazma Ali
Muazma Ali 2019 年 10 月 4 日
No i was thinking of character vectors and I got my answer yesterday that I accepted :)

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