How to implement a formula involving several elements of the same vector?
4 ビュー (過去 30 日間)
古いコメントを表示
Suppose we have two row vectors
Time = [ 1 2 3 4 5 6 7 8 9 10];
width= [0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0]; % width of peaks
There is a formula for peak resolution = (t2-t1)/(2*(w2+w1)), where t2 is element of Time(1,2) and t1 is element of Time(1,1). Similarly, w1 and w2 correspond to elements width(1,1) and width(1,2) respectively. With that one should be able to generate a row vector with 9 elements instead of individually calculating those nine values. In such cases how should we implement a formula involving several elements of the same vector?
Could someone also point out an intermediate level reference which discusses the sytax for operating on several elements of the same row or column vector to produce another vector of different dimension such as in this case? Thanks.
0 件のコメント
採用された回答
Shubham Gupta
2019 年 9 月 23 日
編集済み: Shubham Gupta
2019 年 9 月 23 日
There are several way to do this, but most basic would be to use 'for' loop to get the feeling of how Matrix indexing works:
PeakResolution = zeros(1,length(Time)-1)
for i = 1:length(Time)-1
PeakResolution(i) = (Time(i+1)-Time(i))/(2*(width(i+1)+width(i)));
end
Once you get the feel of it, you can use functions or inline indexing to make your work easy. For e.g. to calculate difference between consecutive elements can be achieved using 'diff'. So, numerators for peak resolution can be written as:
PeakResolution_num = diff(Time); % diff function
% or
PeakResolution_num = Time(2:end)-Time(1:end-1); % inline indexing
and to take mean of consecutive numbers you can use movmean (only for matlab version above 2016a), so denominators become :
PeakResolution_den = movmean(width,[0,1])*2; % movmean function
PeakResolution_den(end) = [];
% or
PeakResolution_den = (width(2:end) + width(1:end-1)) % inline indexing
Now, you can simply use division to calculate PeakResolution:
PeakResolution = PeakResolution_num./(2*PeakResolution_den);
I hope it helps !
5 件のコメント
その他の回答 (1 件)
madhan ravi
2019 年 9 月 23 日
編集済み: madhan ravi
2019 年 9 月 23 日
https://in.mathworks.com/company/newsletters/articles/matrix-indexing-in-matlab.html - for better understanding
peak_resolution = (Time(2:end)-Time(1:end-1))./...
(2*(Width(2:end)+Width(1:end-1))) % if understood correctly
doc colon
doc end
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!