How to generate random matrix from another one?
6 ビュー (過去 30 日間)
古いコメントを表示
Hi!
I have a 18 x 57x11 matrix .
How can I make a new random matrix (the same size) , which is generated by "shuffling" the values of the original matrix?
A lot thanks in advance!
1 件のコメント
Adam Danz
2019 年 9 月 19 日
編集済み: Adam Danz
2019 年 9 月 19 日
Ha! You got 3 different approaches that use randperm() and reshape().
By the way, your data is not a matrix. A matrix is 2 dimensional, with rows and columns. Your data contains a 3rd dimension which makes it an array. All 3 answers will work no matter how many dimensions are in the input.
採用された回答
Adam Danz
2019 年 9 月 19 日
編集済み: Adam Danz
2019 年 9 月 19 日
You can use randperm() to shuffle the values of array 'm'.
% Original array
m =rand(180, 57, 11);
% Random permutation index
randpermIdx = randperm(numel(m));
% m shuffled
mShuffle = reshape(m(randpermIdx), size(m));
To convince yourself that mShuffle is merely a random reorganization of m with no additional or missing values or duplicate samples, use this line below which should return True.
isequaln(sort(m(:)),sort(mShuffle(:)))
その他の回答 (2 件)
Adam
2019 年 9 月 19 日
newMatrix = reshape( oldMatrix( randperm( numel( oldMatrix ) ) ), size( oldMatrix ) );
should work, though I'm sure there are neater ways.
参考
カテゴリ
Help Center および File Exchange で Creating and Concatenating Matrices についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!