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I am not getting the correct answer when using datetime function

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gsourop
gsourop 2019 年 9 月 17 日
コメント済み: Guillaume 2019 年 9 月 17 日
Hi everyone,
I am using the following function
datetime(1,43100,1)
but instead of getting '31/12/2017' as an answer (as given from Excel), I am getting 01-Aug-3592. Apparently, I am missing something in the datetime function but don't know what it is.
Thanks in advance for your time.

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採用された回答

dpb
dpb 2019 年 9 月 17 日
>> datetime(43100,'ConvertFrom','excel')
ans =
datetime
31-Dec-2017 00:00:00
>>
You tried converting from (yr,mo,day) --> (1, 43100, 1) instead.

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gsourop
gsourop 2019 年 9 月 17 日
Thank you very much for the answer! How can I ignore the time part. I want to end up just with '31-Dec-2017' instead of '31-Dec-2017 00:00:00' .
Guillaume
Guillaume 2019 年 9 月 17 日
The time part is always part of a datetime (hence the time in the name). You can avoid displaying it by changing the Format property:
>> datetime(43100,'ConvertFrom','excel', 'Format', 'dd-MM-yyyy')
ans =
datetime
31-12-2017
>> datetime(43100,'ConvertFrom','excel', 'Format', 'eee dd MMM yyyy')
ans =
datetime
Sun 31 Dec 2017
but note that the time part will still be taken into account for calculations (like date difference) whether or not it is displayed. Excel does the same.

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その他の回答 (1 件)

Ted Shultz
Ted Shultz 2019 年 9 月 17 日
編集済み: Ted Shultz 2019 年 9 月 17 日
You are using
t = datetime(Y,M,D)
Year = 1
month = 43100
day = 1
That is not what you intend I assume.
I think you want:
t = datetime(43100,'ConvertFrom','excel')

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