# Sorting and averaging matrices

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HT 2019 年 9 月 9 日
コメント済み: Matt J 2019 年 9 月 16 日
1. I have two matrices. One for example is A = 520 x 1 and it has numbers from 1-8 which are not in order. For every number in this matrix, I have corresponding 1000 samples in another matrix B 520 x 1000. I want to first sort A and arrange numbers from 1-8 for every 8 rows. So output should be (1,2,3,4,5,6,7,8,1,2,3,4,5 and so on) and arrange corresponding values in B also such that they match.
2. Once this is done, I want to average every 5 rows of B and store it in a new matrix which will be 104 x 1000.
Thanks for the help in advance!
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HT 2019 年 9 月 9 日
It will be a multiple of 8 always. I just took 100 as a random number. I will edit the main question, thank you.

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### 採用された回答

Matt J 2019 年 9 月 9 日

[~,idx]=sort( reshape(A,8,[]) ,1);
[m,n]=size(idx);
C=reshape(B,m,n,[]);
[m,n,p]=size(C);
idx=idx+(0:n-1)*m+reshape(0:p-1,1,1,p)*(m*n);
C=mean(reshape(C(idx),5,[]));
result=reshape( C ,m*n/5,[]);
##### 8 件のコメント表示非表示 7 件の古いコメント
Matt J 2019 年 9 月 16 日
[Asorted,idx]=sort( reshape(A,8,[]) ,1);

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