apply condition on Matrix?

if i have a matrix B=[1111000] and another integer T=4 i want to apply while loop if number of One's in B>=T how should i write it to get desire condition

[madhan ravi]

What have you tried for your homework?

[Ali Mukhtar]

i apply a for loop and put while condition until B matrix is have 1's but that is not correct

[madhan ravi]

Post the code that you tried.

[youcha]

Can you please explain more of what do you want to do with your while loop? It should be in a form of : I want to do action B while the condition A is true. Your condition in this ase is B>=T while your action is not clear

[Ali Mukhtar]

if i can count the number of 1's in B matrix i can apply the condition

[Ali Mukhtar]

for i=1

for j=1:n %n= number of one in matrix B

while B(i,j)>=T

end

[madhan ravi]

hint: If one add one or else continue

[Ali Mukhtar]

dnt understand in which one i have to add one? can i count number of 1's in B matrix?

[madhan ravi]

Your goal is to count the number of ones in B and then finally check if it's greater than or equal to T , is that right?

[Ali Mukhtar]

yes exactly

[madhan ravi]

Why not use a for loop? Is loop necessary?

[Ali Mukhtar]

not it is not neccesary this was last what i tried so sent it to you

Answer 1

[madhan ravi]

Just use logical indexing "==" to see the values equal 1 and use nnz() and then use >= T if you get 1 it's true else false.

help ==
help nnz
help >=

[Ali Mukhtar]

nnz()?

[madhan ravi]

help nnz % will tell you what it actually does [hint: this is to count the no of ones present in B]

[Ali Mukhtar]

can you please write few code lines it become more and more complex

[madhan ravi]

nnz(B==1) >= T
%^^^^^^^^--- counts the number of ones

[Ali Mukhtar]

we can use it with while loop

while or if nnz(B==1)>= T ?

Answer 2

[David Hill]

If B is a 1 by x vector of 1's and 0's (B = [1,1,1,1,1,0,0,0,0,0])

while sum(B)>T

if B is a 1 by x character array (B = '1111100000')

while sum(double(B)-48)>T

Your matrix B is not described well above, it looks like a single number.

[Ali Mukhtar]

while sum(double(B)-48)>T

B is array which contains 1's and 0's . in above code line can you explain why you use 48 and subtract it from B

[David Hill]

If your array is a character array '111110000', then I converted to a number array which is a ascii representative of each character and subtract 48=='0' to get an array of 1's and 0's. If you already have an array of 1's and 0's you don't need to do this.

[Ali Mukhtar]

but i dnt know if my value is exactly 111110000 so subtracting it from 48 is not fesible . if you show result by compiling it i can use it also