Fill an array with different size vectors

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Diego R
Diego R 2019 年 9 月 5 日
回答済み: Jos (10584) 2019 年 9 月 5 日
I have different sized vectors and an array to fill
A=[1,2,3,4];
B=[5,6];
C=[7,8,9];
ARRAY=zeros(5);
And I want to reach this:
OBJECTIVE =
1 2 3 4 0
5 6 0 0 0
7 8 9 0 0
0 0 0 0 0
0 0 0 0 0
Any idea? Also if there is any way to extend vectors to certain length I highly appreciate to know.

採用された回答

Stephen23
Stephen23 2019 年 9 月 5 日
編集済み: Stephen23 2019 年 9 月 5 日
For an arbitrary number of vectors use a cell array, then looping is trivial:
>> D = {[1,2,3,4],[5,6],[7,8,9]};
>> M = zeros(5,5);
>> for k = 1:numel(D), M(k,1:numel(D{k})) = D{k}; end
>> M
M =
1 2 3 4 0
5 6 0 0 0
7 8 9 0 0
0 0 0 0 0
0 0 0 0 0

その他の回答 (3 件)

the cyclist
the cyclist 2019 年 9 月 5 日
Here is one straightforward way:
A=[1,2,3,4];
B=[5,6];
C=[7,8,9];
ARRAY=zeros(5);
ARRAY(1,1:numel(A)) = A;
ARRAY(2,1:numel(B)) = B;
ARRAY(3,1:numel(C)) = C;

Diego R
Diego R 2019 年 9 月 5 日
Thank you both! I'd never had found this "numel" by myslef.

Jos (10584)
Jos (10584) 2019 年 9 月 5 日
A=[1,2,3,4];
B=[5,6];
C=[7,8,9];
[ARRAY, tf] = padcat(A,B,C) % pad with NaNs
ARRAY(~tf) = 0 % replace those NaNs with zeros
PADCAT concatenates vectors of unequal lengths by padding them with NaNs. It is available for free on the File Exchange

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