Dealing with wrong input
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How do I avoid this error? I would like for users, if they enter a string instead of number to told "Those are not the instructions, please try again"
4 件のコメント
回答 (2 件)
Nicolas B.
2019 年 9 月 3 日
編集済み: Nicolas B.
2019 年 9 月 3 日
Okay, then I would use the exception catching method:
str = '';
num = NaN;
while isnan(num)
try
num = input('Please enter your guess: ');
catch
disp('You must give a valid number!');
num = NaN;
end
end
1 件のコメント
Rik
2019 年 9 月 3 日
That's also possible, although I think it would make slightly more sense to use Stephen's method, because then it also isn't possible to provide a variable name.
If you define a=9; before your loop, you can enter a in the prompt and it will pass the test. With Stephen's code, that is not possible.
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