find all elements (cells) of a single element (cell) in cell array

MA さんによって質問されました 2019 年 8 月 28 日

最新アクティビティ MA さんによってコメントされました 2019 年 8 月 28 日

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I have the following cell array (c) which is 3*2. Now I want to find all elements of lets say c{1,1} which is [3,2]. The answer that I wish to have is (2) which refers to the index of these elements separately. Any possible ideas? thanks

c=
{[3,2]}        	{[4,1]}
{3}	        {2}
{4}	        {1}

3 件のコメント

Adam Danz on 28 Aug 2019

I don't understand, "The answer that I wish to have is (2) which refers to the index of these elements separately"

MA on 28 Aug 2019

The second row of (c) contains {3} {2} which is actually the same as c{1,1} [3,2] but c{1,1} is combind together. So, 2 here refers to the second row.

Adam Danz 2019 年 8 月 28 日

I see. So you want to return the row index of C that, when horizontally concatented, equals the vector in C{1,1}.

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Answer by MA on 28 Aug 2019

Accepted Answer

I found the answer if anyone is looking for something similar

for i=2:size(c,1)
if (isequal(c{1,1},cell2mat(c(i,:))))
index=i;
end
end

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Adam Danz 2019 年 8 月 28 日

If the idea is to return the row index of c that matches c{1,1}, here is an alternative.

% This line returns the logical index
index = cellfun(@(x)isequal([x{:}],c{1,1}),mat2cell(c,ones(size(c,1),1),2)); 

% This line returns the linear index (matching your for-loop)
index = find(cellfun(@(x)isequal([x{:}],c{1,1}),mat2cell(c,ones(size(c,1),1),2))); 

MA 2019 年 8 月 28 日

Thanks alot. It really helps

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回答者: Luna 2019 年 8 月 28 日

Maybe you can try this piece of code:

cellSizes = cellfun('prodofsize',c);
elementIndices = [];
elementValues = [];
for i = 1:numel(cellSizes)
    for j = 1:cellSizes(i)
     tempVar = c{i}(j);
     elementValues = [elementValues,tempVar];
     elementIndices = [elementIndices,find(c{i} == tempVar)];
    end
end

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