inputparser fails to accept correct value
7 ビュー (過去 30 日間)
古いコメントを表示
I'm currently trying to get the inputparser for my function to work. My code looks like this:
function [] = Test2 (BW,varargin)
defMethod = 2;
p = inputParser;
validImage = @(x) islogical(x);
addRequired(p,'BW',validImage);
addParameter(p,'method',defMethod,@(x) isinteger(x) && (x<3) && (x>0));
parse(p,BW,varargin{:});
Running this codes yields the following result:
Test2(BW,'method',1);
The value of 'method' is invalid. It must satisfy the function: @(x)isinteger(x)&&(x<3)&&(x>0).
Does anyone know what is causing this behaviour?
Ty for your help!
2 件のコメント
採用された回答
Adam Danz
2019 年 8 月 18 日
編集済み: Adam Danz
2019 年 8 月 18 日
isinteger(1) % = FALSE
This matlab function (which often causes confusion) does not determine if the input has an integer value. It determines if the intput is an interger-type (int8, int16, etc...). The input 1 is of class double, not integer-type.
If you need to determine if the input is an integer value,
@(x) mod(x,1)==0 && (x<3) && (x>0));
3 件のコメント
Adam Danz
2019 年 8 月 18 日
編集済み: Adam Danz
2019 年 8 月 18 日
Also, this
validImage = @(x) islogical(x);
addRequired(p,'BW',validImage);
can be simplified to this
addRequired(p,'BW',@islogical);
but if you want to accept true, false, 1, 0,
validImage = @(x) islogical(x) || (isnumeric(x) && ismember(x,[0,1]));
addRequired(p,'BW',validImage);
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Argument Definitions についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!