- What is the result of size(im) ?
- When you say you want to "add these values to the image" do you mean you want to concatenate them (as mentioned in your title) and if so, where should that vector be inserted?
concatenating arrays and matrix
4 ビュー (過去 30 日間)
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Hi all I trying to get a simple syntax to add this constant to image values
im=imread(im)
im=rgb2gray(im)
so now that im is now the gray scale image
i am try to add these values to the image
C1=[10,20,50,100]
Can profesional provide an example of how this is done in the simplest form using a for loop?
thank you in advance!!!
7 件のコメント
Adam Danz
2019 年 8 月 16 日
編集済み: Adam Danz
2019 年 8 月 16 日
If your array is 5 x 5 you cannot concatenate a vector with only 4 elements!
Concatenation involves joining two arrays. Here are two examples.
% Horizontal concatenation
A = [1 2 3;
4 5 6];
B = [11 12 13;
14 15 16];
C = [A,B]
C =
1 2 3 11 12 13
4 5 6 14 15 16
% Vertical concatenation
C = [A; B]
C =
1 2 3
4 5 6
11 12 13
14 15 16
Notice that the size of A and B are equal in the dimensions being concatenated. Here's an example that would FAIL.
X = [1 2 3];
Y = [1 2 3 4];
Z = [X,Y]; % This works
Z2 = [X; Y]; % This doesn't work!
To learn more:
採用された回答
Walter Roberson
2019 年 8 月 16 日
Borrow my code from your previous question https://www.mathworks.com/matlabcentral/answers/475006-threshold-multiple-values-at-the-same-time which had
nd = ndims(YourImageArray);
Thresholded_arrays = bsxfun(@le, YourImageArray, reshape([50, 100, 150, 200], [ones(1,nd), 4]) );
Instead of @le you would use @plus
nd = ndims(YourImageArray);
Incremented_arrays = bsxfun(@plus, YourImageArray, reshape(uint8([50, 100, 150, 200]), [ones(1,nd), 4]) );
5 件のコメント
Walter Roberson
2019 年 8 月 17 日
C1 = [10,20,50,100];
numC1 = length(C1);
imrgb = imread(FILENAME);
imgray = rgb2gray(imrgb);
[r, c] = size(imgray);
output = zeros(r, c, numC1, class(imgray)); %probably it will be uint8
for C1idx = 1 : numC1
this_C1 = C1(C1idx);
output(:,:,C1idx) = imgray + this_C1;
end
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