part of file name

If I have a file name such as ' Hello_World_2020 ', I want to take the part between the underscores ' world ', how I would do that.

Regards.

Answer 1

[Walter Roberson]

s = 'Hello_World_2020';
c = regexp(s, '_', 'split') ;
c{2}

You can also use strsplit() instead of regexp. On the other hand, strsplit() invokes regexp internally.

[ayman mounir]

Thanks a lot, it works

[Adam Danz]

"If I write s=Hello_World_year_2020. the answer would be 'Hallo_year'. what I should modify?"

@ayman, it's not clear what rules you're following.

• "Hello_World_2020" --> "World": This removes everything before and after the underscores, including the underscores.
• "Hello_World_year_2020" --> "Hello_year": This doesnt' follow that rule.

I think Walter's solution will come in handy but you'll need to explain the rule you're following.

[ayman mounir]

clear, thanks

Answer 2

[Adam Danz]

s = 'Hello_World_2020'; 
c = regexp(s,'_(.*)_','tokens');
c = c{1}{1};

c =
    'World'

[ayman mounir]

It is really helpful, thank a lot

Answer 3

[madhan ravi]

s=' Hello_World_2020 ';
[~,Wanted]=regexp(s,'_(.*)_','match','tokens');
Wanted{:}

[ayman mounir]

Thanks, It is really helpful, woudl mind to explain how the exprsion works. for exmaple If I write s=Hello_World_year_2020. the answer would be 'Hallo_year'. what I should modify?

Regards

[madhan ravi]

As Adam commented , I had the same thoughts too straight away.

Answer 4

[Jan]

s = ' Hello_World_2020 '
c = strsplit(s, '_')
c{2}