Subscript in stackedplot DisplayLabels

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Sebastian Sprunck
Sebastian Sprunck 2019 年 7 月 18 日
編集済み: Yair Altman 2024 年 2 月 13 日
Hello everyone,
I'm trying to build a stacked plot with 3 graphs using Matlab 2018b's stackedplot-function. I'd like to write the corresponding DisplayLabels in TeX-style so that I can use subscripts, as can be done in regular plots without problem using e.g.
'T_{r}'
When I create a stackedplot using below code though, the labels are printed 'as is' instead of as a subscript:
s = stackedplot(f,If,'DisplayLabels',{'T_{r} = 50 ns','T_{r} = 20 ns','T_{r} = 10 ns'});
StackedPlot.PNG
I've tried accessing Interpreter-properties and even setting
set(0,'defaultTextInterpreter','latex');
but couldn't get it to work as intended.
Can anyone please tell me how to do that?
Best regards
Sebastian
  4 件のコメント
Sebastian Sprunck
Sebastian Sprunck 2019 年 7 月 30 日
Hmmm, I suspected something like that. Guess that's the curse of new functionalities ;)
Building my own subplot was my first attempt, but I'd like the x axis to only show at the bottom, as is the case in the stackedPlot variant. If I could get the labels to work as I want them, it would mean much "cleaner" code for my script.
Adam Danz
Adam Danz 2019 年 7 月 30 日
編集済み: Adam Danz 2019 年 7 月 30 日
Yeah, there are a few newer plotting functions that have a bunch of features on lockdown such as heatmap() and stackedplot(). I avoid using them which is unfortunate since they have some nice added features but when you can edit the basic, they become less useful.

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Yair Altman
Yair Altman 2019 年 7 月 31 日
編集済み: Yair Altman 2024 年 2 月 13 日
You can access the individual stacked-axes' properties via the hidden sub-property Axes of the stackedplot's AxesProperties property, and then modify the YLabel's Interpreter property to 'tex' or 'latex' (it's 'none' by default).
For example, to change the middle (2nd) YLabel:
s = stackedplot(...);
drawnow % ensure that the plot is updated before proceeding
axesProps = struct(s.AxesProperties(2)); % using struct() is undocumented
axesProps.Axes.YLabel.Interpreter = 'tex';
Note that using struct() to access internal object properties is undocumented.
  6 件のコメント
Ron
Ron 2024 年 2 月 4 日
編集済み: Ron 2024 年 2 月 4 日
Thankyou for responsding sir but I did try but it didnt do anything except the warning.
or there is something wrong with my code??
ss=stackedplot(error,'LineWidth',1.5);
ss.DisplayLabels = [sample_name,sample_name(1)+"_{abc}"];
axesProps = struct(ss.AxesProperties(4)); % using struct() is undocumented
axesProps.Axes.YLabel.Interpreter = 'tex';
Adam Danz
Adam Danz 2024 年 2 月 13 日
The call to struct in this context is undocumented. It needs to be called after the stackplot is generated. This can be done by adding a drawnow before calling struct.

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