hi every one, i need to ask a question, thank you

1 回表示 (過去 30 日間)
mina massoud
mina massoud 2019 年 6 月 30 日
コメント済み: mina massoud 2019 年 7 月 1 日
if i have a row vector like this A=[ 0 1 1 1 0 0 1 1 0 1 ]
and another vector B=[ 1 2 3 4 5 6 ]
and i need to put the element of B in order in A when the element is equal to 1
so if it can possibile i need to return a vector with the dimensions of B like this [ 0 1 2 3 0 0 4 5 0 6 ] , how can i do it if it's possibile to do it in matlab
thank you

採用された回答

Image Analyst
Image Analyst 2019 年 6 月 30 日
Try this:
A=[ 0 1 1 1 0 0 1 1 0 1 ]
B=[ 1 2 3 4 5 6 ]
out = A % Initialize
out(logical(A)) = B % Assign B to "1" locations in A
It give you what you asked for.

その他の回答 (3 件)

Matt J
Matt J 2019 年 6 月 30 日
編集済み: Matt J 2019 年 6 月 30 日
result=sparse(1,find(A),B)

Catalytic
Catalytic 2019 年 6 月 30 日
A=double(A);
A(logical(A))=B;

Matt J
Matt J 2019 年 6 月 30 日
編集済み: Matt J 2019 年 7 月 1 日
[i,j]=find(A(:));
result=accumarray([i,j],B(:),size(A.')).'
  4 件のコメント
Image Analyst
Image Analyst 2019 年 7 月 1 日
I think it's because the poster did not see what she wanted to see. So instead of seeing:
0 1 2 3 0 0 4 5 0 6
like she asked for, you see
result =
(1,2) 1
(1,3) 2
(1,4) 3
(1,7) 4
(1,8) 5
(1,10) 6
mina massoud
mina massoud 2019 年 7 月 1 日
sorry i accept it by mistake , now i accept your answer that is the best answer
thank's very much for all of you, i really appraciate it

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