How to change 0 to 1 and update a matrix
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clc
clear all
close all
b1 = [10; 20 ; 30 ; 40];
A = [0 20 0 10 ; 20 0 30 0 ; 0 30 0 10 ; 20 0 10 0];
s = size(b1);
x = randi([0 1],s)
G = [];
[ n m ] = size(x);
for i = 1 : n
for j = 1 : m
G(:,i) = x(:,j)
a = find(G(: , i) == 0 , 1 , 'first')
[x y] = size(G(:,i))
for k = 1:y
G(: , k) = 0;
G(a , k) = 1
end
end
i = i + 1;
j = j + 1;
end
This prob wil work only the first time. I want the matrix to take a column, find where the first 0 is and change it to 1. Then proceed to the next line and do the same but keep the first column and not change it to 0s. Final solution must look like
x =
0
1
0
0
(x changes randomly with 0 and 1 )
G =
1 0 0 0
0 1 0 0
0 0 1 0
0 0 0 1
I would appreciate any answer :)
採用された回答
Andrei Bobrov
2019 年 6 月 21 日
編集済み: Andrei Bobrov
2019 年 6 月 22 日
n = numel(x1);
y1 = ~x1;
% if MATLAB >= R2016b
k = y1.*eye(n);
% if MATLAB <= R2016a
k = bsxfun(@times,y1,eye(n));
out = [x1, zeros(n,n-1)];
p = find(y1);
out(:,2:numel(p)+1) = k(:,p);
4 件のコメント
Andrei Bobrov
2019 年 6 月 22 日
You use old MATLAB.
Replace this expression with the following:
k = bsxfun(@times,y1,eye(n));
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