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could anyone help me how to select four maximum values of each row in a matrix size(10,8)

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I am having a matrix of size(10,8) (% 10 rows and 8 columns)
I want to select 4 maximum values from each row by having the result of matrix size(4,8)(%4 rows and 8 columns)
Could anyone please help me on this.

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KALYAN ACHARJYA
KALYAN ACHARJYA 2019 年 5 月 29 日
編集済み: KALYAN ACHARJYA 2019 年 5 月 29 日
You can do it in multiple ways, let’s consider, the mat1 is matrix having size 10x8
sort_mat=sort(mat1);
result=sort_mat(7:end,:);
Another way as per @madhan ravi comment
sort_mat=sort(mat1,'descend');
result=sort_mat(1:4,:)
See example
>> mat1=rand(10,8)
mat1 =
0.2599 0.5499 0.1839 0.3692 0.5752 0.6477 0.7802 0.8176
0.8001 0.1450 0.2400 0.1112 0.0598 0.4509 0.0811 0.7948
0.4314 0.8530 0.4173 0.7803 0.2348 0.5470 0.9294 0.6443
0.9106 0.6221 0.0497 0.3897 0.3532 0.2963 0.7757 0.3786
0.1818 0.3510 0.9027 0.2417 0.8212 0.7447 0.4868 0.8116
0.2638 0.5132 0.9448 0.4039 0.0154 0.1890 0.4359 0.5328
0.1455 0.4018 0.4909 0.0965 0.0430 0.6868 0.4468 0.3507
0.1361 0.0760 0.4893 0.1320 0.1690 0.1835 0.3063 0.9390
0.8693 0.2399 0.3377 0.9421 0.6491 0.3685 0.5085 0.8759
0.5797 0.1233 0.9001 0.9561 0.7317 0.6256 0.5108 0.5502
>> sort_mat=sort(mat1)
sort_mat =
0.1361 0.0760 0.0497 0.0965 0.0154 0.1835 0.0811 0.3507
0.1455 0.1233 0.1839 0.1112 0.0430 0.1890 0.3063 0.3786
0.1818 0.1450 0.2400 0.1320 0.0598 0.2963 0.4359 0.5328
0.2599 0.2399 0.3377 0.2417 0.1690 0.3685 0.4468 0.5502
0.2638 0.3510 0.4173 0.3692 0.2348 0.4509 0.4868 0.6443
0.4314 0.4018 0.4893 0.3897 0.3532 0.5470 0.5085 0.7948
0.5797 0.5132 0.4909 0.4039 0.5752 0.6256 0.5108 0.8116
0.8001 0.5499 0.9001 0.7803 0.6491 0.6477 0.7757 0.8176
0.8693 0.6221 0.9027 0.9421 0.7317 0.6868 0.7802 0.8759
0.9106 0.8530 0.9448 0.9561 0.8212 0.7447 0.9294 0.9390
>> resul1=sort_mat(7:10,:)
resul1 =
0.5797 0.5132 0.4909 0.4039 0.5752 0.6256 0.5108 0.8116
0.8001 0.5499 0.9001 0.7803 0.6491 0.6477 0.7757 0.8176
0.8693 0.6221 0.9027 0.9421 0.7317 0.6868 0.7802 0.8759
0.9106 0.8530 0.9448 0.9561 0.8212 0.7447 0.9294 0.9390
>>
  3 件のコメント
KALYAN ACHARJYA
KALYAN ACHARJYA 2019 年 5 月 29 日
Yes, thanks answer added!

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その他の回答 (1 件)

Guillaume
Guillaume 2019 年 5 月 29 日
編集済み: Guillaume 2019 年 5 月 29 日
As I commented here (please don't ask the same question multiple times, thus wasting people's time), the simplest way in modern matlab (R2017b or later) is with maxk:
result = maxk(yourmatrix, 4)

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