How to insert a new vector to matrix in every iteration?
15 ビュー (過去 30 日間)
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Hi everyone,
I try to form a matrix that gets the vector elements by using for loop. In other words, I want to save the for loop result in a matrix. You can see my code below and what I want.
for x=1:1:3
for y=4:1:5
z = [x y]'
????
end
end
out =
1 1 2 2 3 3
4 5 4 5 4 5
Could you help me about this 2x6 matrix, please?
0 件のコメント
採用された回答
madhan ravi
2019 年 5 月 18 日
編集済み: madhan ravi
2019 年 5 月 18 日
Trivially done without a loop:
out = [repelem(x,1:numel(x));repmat(y,1,numel(x))]
With loop:
x=1:3;
y=4:5;
ctr=1;
out=zeros(2,numel(x)+numel(y)); % preallocate!
for k=1:numel(x)
for l=1:numel(y)
out(:,ctr) = [x(k) ; y(l)];
ctr=ctr+1;
end
end
Gives:
>> out
out =
1 1 2 2 3 3
4 5 4 5 4 5
3 件のコメント
madhan ravi
2019 年 5 月 18 日
No I don’t and I don’t see how that’s related to the question you originally asked. You'd be better off posting a new question.
その他の回答 (1 件)
Sulaymon Eshkabilov
2019 年 5 月 18 日
編集済み: Sulaymon Eshkabilov
2019 年 5 月 18 日
This one works:
x = [1 1 2 2 3 3];
y= [4 5 4 5 4 5];
z = zeros(2, numel(x));
for ii=1:numel(x)
z(:,ii)=[x(ii), y(ii)];
end
4 件のコメント
madhan ravi
2019 年 5 月 18 日
編集済み: madhan ravi
2019 年 5 月 18 日
I just pointed out the fault which was there and there is no need to get angry with the fact being exposed. If it’s hard just ignore else try to accept the mistake and change it.
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