Display different graphs from a dropdown menu

I want to be able to use a dropdown menu to display different graphs. I have been able to generate the graphs and the dropdown menu. However, when I go to use the dropdown menu I get an error which will be described below. Here is my code:
clear
clc
% create figure and components
fig = uifigure;
ax = uiaxes('Parent', fig, 'Position', [10 10 400 400]);
% Create a plot
x = (-100:100)';
y.A = x.^2;
y.B = x.^3;
p = plot(ax, x, y.A);
p.YData = y.A;
% Create a dropdown component
dd = uidropdown(fig, 'Position', [430 210 100 22],...
'Items', {'A', 'B'},...
'Value', 'A',...
'ValueChangedFcn', @(dd, event) selection(dd,p));
% Create ValueChangedFcn callback
function selection(dd, p)
val = dd.Value;
p.YData = val;
end
The error that I get is as follows:
Value must be a vector of numeric type
Error in dropDownTest2>selection (line 29)
p.YData = val;
Error in dropDownTest2>@(dd,event)selection(dd,p)
Error using matlab.ui.control.internal.controller.ComponentController/executeUserCallback (line 378)
Error while evaluating DropDown PrivateValueChangedFcn.
Thanks for your help

2 件のコメント

Adam Danz
Adam Danz 2019 年 5 月 8 日
What is the value of "val"?
Nev Pires
Nev Pires 2019 年 5 月 10 日
To be honest, I wanted val to be equal to whatever I selected from the dropdown menu. If "A" was selected, it would display the graph: y.A, and if "B" was selected it would display the graph: y.B. The only way I could get anything to display in the first place is with this code. I have no idea how to associate the dropdown menu selections with the respective graphs I want to plot.

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 採用された回答

Adam Danz
Adam Danz 2019 年 5 月 10 日

2 投票

This should do what you're describing. Let me know if you have any questions.
% create figure and components
fig = uifigure;
ax = uiaxes('Parent', fig, 'Position', [10 10 400 400]);
% Create a plot
x = (-100:100)';
y.A = x.^2;
y.B = x.^3;
p = plot(ax, x, y.A);
% p.YData = y.A; %No need for this line
% Create a dropdown component
dd = uidropdown(fig, 'Position', [430 210 100 22],...
'Items', {'A', 'B'},...
'Value', 'A',...
'ValueChangedFcn', @(dd, event) selection(dd,p,y));
% Create ValueChangedFcn callback
function selection(dd, p, y)
switch dd.Value
case 'A'
val = y.A;
case 'B'
val = y.B;
otherwise
error('Did not recognize selection.')
end
p.YData = val;
end

その他の回答 (0 件)

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質問済み:

2019 年 5 月 8 日

回答済み:

2019 年 5 月 10 日

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