creating a new column in a matrix using 'if condition"
1 回表示 (過去 30 日間)
古いコメントを表示
On the following matrix:

I am using the following code which is not giving the right response.
if Reg1(:,3)==0
Reg1(:,10)=0;
else
Reg1(:,10)=a1-b1*Reg1(:,3)+Reg1(:,6);
end
Cannot figure out the issue.
The output is

1 件のコメント
Catalytic
2019 年 4 月 26 日
We have no way of knowing what you consider to be the "right response"....
採用された回答
参考
カテゴリ
Help Center および File Exchange で Creating and Concatenating Matrices についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!