Write a function called get_distance that accepts two character vector inputs representing the names of two cities. The function returns the distance between them as an output argument called distance. For example, the call get_distance('Seattle, WA'

function distance = get_distance(x,y)
[~,~,raw] = xlsread('Distances.xlsx');
col_labels = raw(1,:);
row_labels = raw(:,1);
try
distance = raw{contains(row_labels,y),contains(col_labels,x)};
catch
distance = -1;
end
end
error
Assessment result: incorrectNashville, TN and Las Vegas, NV
Variable distance has an incorrect value.
Assessment result: incorrectRandom city pairs
Variable distance has an incorrect value.
get_distance('Chattanooga, TN','Meads, KY') returned -1 which is incorrect.

1 件のコメント

Given that this question has been tagged "no more answers please!", should one of the answers be accepted and the question be locked?

回答 (22 件)

function distance=get_distance(a,b)
[~,~,raw]=xlsread('Distances.xlsx');
row=raw(1,:);
col=raw(:,1);
for ii=2:length(row)
if strcmp(row(ii),a)
mii=ii;
break;
end
end
for jj=2:length(col)
if strcmp(col(jj),b)
njj=jj;
break;
end
end
if (strcmp(row(ii),a))&&(strcmp(col(jj),b))
distance=raw{mii,njj};
else
distance=-1;
end
end

8 件のコメント

for ii=2:length(row)
mii=ii;
can you tell me why you did 2:length.
and why do mii.
2 becasue the first column, the first row is empty cell
Please explain
row=raw(1,:);
raw(1,:) what this statement means
Walter Roberson
Walter Roberson 2021 年 8 月 19 日
編集済み: Walter Roberson 2021 年 8 月 19 日
To understand what the raw is doing, you need the context
[~,~,raw]=xlsread('Distances.xlsx');
That is, you need to know that raw is being returned as the third output from xlsread()
The third output from xlsread() is a cell array according to the following rules:
  • if the corresponding cell in the spreadsheet is empty, then the cell in the cell array will contain empty (or is it NaN? I forget)
  • if the corresponding cell in the spreadsheet is marked as an date, then the cell in the cell array will contain a MATLAB datetime() object, on new enough versions of MATLAB (older versions the date will show up as excel numeric format, days since Jan 1 1900 with a bug having to do with leap year handling for year 1900)
  • if the corresponding cell in the spreadsheet can be converted to numeric by str2double(), then the cell in the cell array will contain the converted numeric value
  • otherwise the cell in the cell array will contain whatever characters were in the spreadsheet of the cell
raw(1,;) would then be selecting the first row of that cell array.
In the file, the first entry A1 is empty, and columns 2 onward are city names.
Okay ,
if raw(1,;) represents the first row of that cell array then row=raw(,;) should also be selecting the first row. So 'row' is not initialised as a vector ,but in the for loop 'row' is used as a vector ex. row(1) , row(2), ....
@Walter Roberson plz help me
why it shows this type of error
You asked to read a file named Distance.xlsx without passing any directory information. Your current folder is named /users/mss.system.qmc49 . There is no file named Distance.xlsx in your current folder.
You could first cd to where the file actually is. But it is better if you use fullfile to construct a complete path to where the file actually is.
one more
function distance = get_distance(A,B)
[data txt] =xlsread('Distances.xlsx');
ii=0;
jj=0;
for i=2:length(data)
if string(A)==string(txt{1,i})
ii=i;
end
if (string(B)==string(txt{1,i}))
jj=i;
end
end
if (~(jj) || ~(ii))
distance=-1;
else
distance=data(ii-1,jj-1);
end

2 件のコメント

I wish this code was commented. I understand the general idea, but would like to see the logic flow of whoever wrote it.
Olel Arem
Olel Arem 2020 年 5 月 1 日
編集済み: Olel Arem 2020 年 5 月 1 日
function distance=get_distance(city_1,city_2)
n=0;m=0;
[value,name]=xlsread('Distances.xlsx');
for ii=1:size(name,2)
if (strcmp(city_1,name(ii,1)))
n=ii;
end
end
for jj=1:size(name,1)
if (strcmp(city_2,name(1,jj)))
m=jj;
end
end
if(n==0 && m==0 && n==1&&m==1)
distance =-1;
elseif (n>0&&m>0)
distance=value(n-1,m-1);
else
distance=-1;
end

2 件のコメント

if(n==0 && m==0 && n==1&&m==1)
can you explain why we use this line and kindly explain it
Rik
Rik 2022 年 3 月 16 日
That will never be true. n can't be 0 and 1 at the same time. Why this uncommented block of code ever received an upvote is not clear to me.
function distance=get_distance(A,B)
[~,~,All]=xlsread('Distances.xlsx');
p=strcmp(All,A);
q=strcmp(All,B);
r=sum(p(:));
s=sum(q(:));
if ~(r==2&&s==2)
distance=-1;
return
end
a=find(p==1);
b=find(q==1);
distance=All{(a(1)),(b(1))};

2 件のコメント

Nada Hussein
Nada Hussein 2020 年 7 月 20 日
編集済み: Nada Hussein 2020 年 7 月 20 日
can you please explain your code? i don't get the lines:5,6,7,11,12
The ==2 does not make sense to me; it would make sense to me if it were ==1 meaning that exactly one column matched.
Oh wait... the Raw (third) output has the names in the first row and in the first column. The person who wrote the above code assumes that each name will appear exactly once in the header row and once in the header column, for a total of two appearances: that is why the 2. The person also assumes that the order is exactly the same between the rows and columns.
Distance matrices should not be assumed to be symmetric. I would not recommend this version of the code.
function distance = get_distance(x,y)
k=-1;
[~,~,all] = xlsread('Distances.xlsx');
[r c] = size(all)
for i = 1:r
for j = 1:c
if i==1 && j==1
continue;
else
if strcmp(x,all(i,1))==1 && strcmp(y,all(1,j))==1
k= all{i,j};
end
end
end
end
distance = k;
end

2 件のコメント

this doesn't return Distance=-1
Rik
Rik 2020 年 9 月 1 日
It turns out you can't reliably cheat off this page, because some solutions have bugs or flaws. If that weren't the case I would probably be a lot more active in deleting answers.
Ankit singh chauhan
Ankit singh chauhan 2020 年 11 月 29 日
編集済み: Rik 2020 年 11 月 29 日
function distance=get_distance(city1,city2) [~,~,raw]=xlsread('Distance.xlsx') try s=strcmp(raw,city2)
g=strcmp(raw,city1)
[r1,c1]=find(s==1)
[r2,c2]=find(g==2)
distance=raw{r1,r2}
catch
distance=-1
end

1 件のコメント

Rik
Rik 2020 年 11 月 29 日
Still the same question: why did you post this? What does it teach?
Gokul surya Subramanian
Gokul surya Subramanian 2019 年 4 月 17 日
編集済み: Rik 2019 年 7 月 2 日
function distance = get_distance(a,b)
[~,text,raw] = xlsread('Distances.xlsx');
for i=2:size(raw,1)
if strcmp(text{i,1}, a)
break
end
end
if i>=size(raw,1)
distance=-1;
else
for j=2:size(raw,2)
if strcmp(text{1,j}, b)
distance=raw{i,j};
break
end
end
if j>=size(raw,2)
distance = -1;
end
end

13 件のコメント

This code is incorrect for the case where a is found in the last row of text, or b is found in the last column of text.
actually the excel file is already given with the cities arranged in alphabetical orders. so i dont think it should be an issue.
Then there would be a problem if asked to find information about the last city alphabetically.
use following code
function distance = get_distance(a,b)
found = true;
[~,text,raw] = xlsread('Distances.xlsx');
for i=2:size(raw,1)
for j=2:size(raw,2)
if strcmp(text{i,1}, a) && strcmp(text{1,j}, b)
distance=raw{i,j};
found = false;
break
end
end
end
if found
distance = -1;
end
end
Jun Choi
Jun Choi 2020 年 5 月 12 日
what's the purpose of writing "found=true"?
In the above code, the found flag has to be read as the opposite of its normal meaning, as indicating that the data was not found. It would have been clearer if the person had written
function distance = get_distance(a,b)
notfound = true;
[~,text,raw] = xlsread('Distances.xlsx');
for i=2:size(raw,1)
for j=2:size(raw,2)
if strcmp(text{i,1}, a) && strcmp(text{1,j}, b)
distance=raw{i,j};
notfound = false;
break
end
end
end
if notfound
distance = -1;
end
end
The reason to have such a flag at all is that it is possible that the combination of cities was not located in the data, in which case distance = -1 has to be returned.
When I try with a modified version of this code as follows, I get distance = -1 for get_distance('Seattle, WA','Miami, FL'). I couldn't debug this because it would take a long time to get to the index (279, 187) , so it'd be great if someone could point out the semantic error in this code.
For Seattle and Miami, the if condition should be true, so the else block should not have been executed.
function [distance] = get_distance(a, b)
[num, text, raw] = xlsread("Distances.xlsx");
for ii = 2:size(raw,1)
for jj = 2:size(raw,2)
if strcmpi(a,raw{ii,1}) && strcmpi(b, raw{1,jj})
distance = raw{ii, jj};
else
distance = -1;
end
end
end
end
for jj = 2:size(raw,2)
if strcmpi(a,raw{ii,1}) && strcmpi(b, raw{1,jj})
distance = raw{ii, jj};
else
distance = -1;
end
end
You do not end your search as soon as you find a match, so if there is no match on the next jj value, you would replace distance with -1 .
strcmpi(a,raw{ii,1}) && strcmpi(b, raw{1,jj} could anyone explain me this?
a is the name of the first city, as a character vector. b is the name of the second city, as a character vector.
raw{ii,1} is the contents of the character vector that lives at row #ii, column 1, of the raw data. column 1 is a list of "from" cities.
raw{1,jj} is the contents of the character vector that lives at column #jj of row 1 of the raw data. row 1 is a list of "to" (destination) cities.
strcmpi() is a comparison of two character vectors ignoring case -- so for example 'Los Vegas' and 'los Vegas' would be considered to be the same.
Thus the code is seeing if the first city name matches the contents of the name of the city in the current row, number ii, and (&&) the second city name matches the contents of the name of the city in the current column, number jj.
@Walter Roberson do you understand the above code? could you please explain me the code which i metioned above?
this one also 'if string(A)==string(txt{1,i})' why 1?
For this particular homework problem, the reference data has been defined to be stored in a xlsx file that has the format
<empty> <cityname1> <cityname2> <cityname3> ...
<cityname1> distance11 distance12 distance13 ...
<cityname2> distance21 distance22 distance23 ...
where the <cityname> are text such as 'Los Vegas, Nevada' and 'Wawa, Ontario', and the distances are numeric.
When you use xlsread on the file and ask for the second output, the output will be a cell array of character vectors, with the character vectors being present where the original data had text, and being empty where the original data had numbers. So it might look something like
txt = {
[], 'LA', 'Wawa', 'Lima'
'LA' [] [] []
'Wawa' [] [] []
'Lima' [] [] []
}
When you use txt{1,i} you would therefore be accessing the [] at the beginning, or one of the city names, 'LA', 'Wawa', 'Lima' -- you would be reading out of row #1 from the txt cell array. txt{ROWNUMBER, COLUMNNUMBER} is the general form.
Using string() on a character vector converts it from being a character vector to being a scalar "string" object. So the line
if string(A)==string(txt{1,i})
converts character vector inside A to a string() object; and then extracts the content of column #i from row 1 of the cell array named txt and converts that content into a string() object. Then the line uses == between the string objects.
The reason someone would do that is that == is defined between string objects to return true of the strings have the same content, and false if the strings do not have the same content, with false being returned if they are different because they have different lengths. So string('LA') == string('Wawa') is perfectly good code that will not have a problem.
But == is not defined between character vectors in the same way, In particular, == between character vectors will fail if they both have more than one character and the lengths do not match. 'LA'=='Wawa' would fail complaining that the array dimensions do not agree (meaning that the lengths are different.) To compare character vectors taking into account they might be different lengths, use strcmp(), as in strcmp('LA', 'Wawa')
function distance = get_distance(a,b)
[~,text,raw] = xlsread('Distances.xlsx');
for i=2:size(raw,1)
if strcmp(text{i,1}, a)
break
end
end
if i>=size(raw,1)
distance=-1;
else
for j=2:size(raw,2)
if strcmp(text{1,j}, b)
distance=raw{i,j};
break
end
end
if j>=size(raw,2)
distance = -1;
end
end
function d = get_distance(c1,c2)
[~,~,city] = xlsread("Distances.xlsx");
[r,c] = size(city);
row = city(1:end,1);
col = city(1,1:end);
ccr=sort(contains(row(2:end),c1));
ccc=sort(contains(col(2:end),c2));
if ccr'==ccc
ir = find(strcmp(row,c1));
ic = find(strcmp(col,c2));
d = city{ir,ic};
else
d=-1;
end

5 件のコメント

im facing a problem here
when the inputs are Nashville and las vegas,, seems to return d as -1
Remember that contains() is case sensitive, so if the entry in the file had Las Vegas and you ask to search for las vegas then you would not find a match.
this errors are coming
What happens when you use the debugger to trace the flow of your code?
function distance=get_distance(L1,L2)
[n,~,r]=xlsread('matlab_dist.xlsx');
i=1;j=1;
[R C]=size(n);
while(~(strcmp(L1,r(1,i))) && i<=R)
i=i+1;
end
while(~(strcmp(L2,r(j,1)))&& j<=C)
j=j+1;
end
j=j-1;i=i-1;
if(~(strcmp(L1,r(1,i+1))) || ~(strcmp(L2,r(j+1,1))))
distance=-1;
else
distance=n(i,j);
end
end
function distance=get_distance(c1,c2)
[num txt raw]=xlsread("Distances.xlsx");
a=0;b=0;
for ii=2:337
if strcmp(txt{1,ii},c1)
a=ii;
elseif strcmp(txt{1,ii},c2)
b=ii;
end
end
if a && b
distance=num(a-1,b-1);
else
distance=-1;
end

1 件のコメント

Why 337?
Your code assumes that Distances contains data of a particular size. It also assumes that the number of rows and columns is the same. It further assumes that there is never a case where the two different cities happen to occur at the same row and column number. For example,
* apple orange grapefruit
orange 2 0 3
grapefruit 1 3 0
apple 0 2 1
Your code would fail for (say) orange, grapefruit because it assumes that when it finds orange in column 3, that it is not possible to also happen to find grapefruit in row 3.
function distance=get_distance(a,b)
[~,~,raw]=xlsread('Distances.xlsx');
row=raw(1,:);
col=raw(:,1);
for ii=2:length(row)
if strcmp(row(ii),a)
mii=ii;
break;
end
end
for jj=2:length(col)
if strcmp(col(jj),b)
njj=jj;
break;
end
end
if(njj > 0 && mii > 0)
distance = raw{mii,njj};
elseif(njj == 1 && mii == 1)
distance = -1;
elseif(njj == 0 && mii == 0)
distance = -1;
else
distance=-1;
end
end
Error:
distance = get_distance('g, WA','Miagmi, FL')
Unrecognized function or variable 'njj'.
Error in get_distance (line 19)
if(njj > 0 && mii > 0)
Help me understand this error.

1 件のコメント

亮 张
亮 张 2020 年 6 月 24 日
I think you might remove two elif condition commands and set default "mii" and "njj" as 0, then it could work.
function y = get_distance(city_1,city_2)
global raw;
[~,~,raw] = xlsread('Distances.xlsx');
%fetching cities in rows
r_city = {};
for i = 1:337
r_city{1,i} = raw{1,i};
end
%fetching cities in columns
c_city = {};
for j = 1:337
c_city{1,j} = raw{j,1};
end
%searching city_1
search_c1 = strcmp(c_city,city_1);
%searching row
for ii = 1:337
if (search_c1(1,ii) == 1)
break
else
ii = 1;%if the city is not found ii will give 1
end
end
%searching city_2
search_c2 = strcmp(r_city,city_2);
%searching column
for jj = 1:337
if (search_c2(1,jj) == 1)
break
else
jj = 1;%if the city is not found jj will give 1
end
end
if ((ii == 1) || (jj == 1)) % if the city is not found
y = -1;
else
y = raw{ii,jj}(1,1);
end
end

2 件のコメント

What will you do when the Distances.xlsx file does not have exactly 337 rows and columns ?
Thanks, I think I'll first measure the size or length of 'raw'.
M NAGA JAYANTH AVADHANI
M NAGA JAYANTH AVADHANI 2020 年 7 月 28 日
編集済み: M NAGA JAYANTH AVADHANI 2020 年 7 月 28 日
This works perfectly.
function distance = get_distance(city1,city2)
[~,~,raw] = xlsread('Distances.xlsx');
row = raw(1,:);
col = raw(:,1);
mi =0;mj =0;
for i = 2:length(row)
if strcmp(row(i),city1)
mi = i;
end
end
for j = 2:length(col)
if strcmp(col(j),city2)
mj = j;
end
end
if mi> 1 && mj>1
distance = raw{mi,mj};
else
distance = -1;
end
end

5 件のコメント

what is the requirement of mi =0;mj =0; in line 3
Rik
Rik 2020 年 8 月 14 日
Look through the rest of the code. Where are values for mi and mj set? Only inside if statements. Is it guaranteed that those lines are reached? What would be the consequence of those variables not being set?
please help me .why it does not works?
Capulus_love
Capulus_love 2020 年 8 月 12 日
編集済み: Capulus_love 2020 年 8 月 12 日
function distance = get_distance(a,b)
[~,~,excel] = xlsread('Distances.xlsx');
col = excel(1,:);
row = excel(:,1);
x=size(col)
y=size(row)
col_count = 1;
row_count = 1;
for i = 2 : x(2)+1
col_count = col_count + 1;
if contains(col{i},a) == 1
break
end
end
for j = 2 : y(1)+1
row_count = row_count + 1;
if contains(row{j},b) == 1
break
end
end
if (col_count > 337) || (row_count > 337)
distance = -1
else
distance = excel{row_count,col_count}
end
end
% why Non-existent city is not solved...???

3 件のコメント

i passed the problem using try.. catch..end
but, still i don't know why this code is not working
Rik
Rik 2020 年 8 月 12 日
Where are you checking if a city exists in the list? What happens on each line if that happens?
if (col_count > 337) || (row_count > 337)
What would happen if they changed the data file to one that had (for example) 500 cities?
function distance = get_distance (ct1, ct2)
[~,~,raw]= xlsread("Distances.xlsx");
f_row = raw(1,:);
f_col = raw(:,1);
flag = false;
distance = -1;
for n=1:length(f_row)
for m=1:length(f_col)
if string(f_row(n)) == ct1 && string(f_col(m)) == ct2
flag = true
distance = raw{n,m};
end
end
end
end

2 件のコメント

Yan Li
Yan Li 2020 年 9 月 4 日
THE CODE PASSED ALL TESTS, MIGHT NOT BE THE SMARTEST, BUT A WORKING ONE.
Surprisingly enough this works.
string({'foo'})=='foo'
Why did you decide to post this? What does it teach?
Also, why are you setting a flag, but not returning it or using it anywhere?
Ahmed Saleh
Ahmed Saleh 2021 年 3 月 28 日
編集済み: Ahmed Saleh 2021 年 3 月 28 日
function distance = get_distance(city1,city2)
[~,~,distances] = xlsread('Distances.xlsx');
num1=0;
num2=0;
s=size(distances);
for i=2:s(1)
logic=strcmp(city1,distances{i,1});
if logic== true
num1=i;
break
end
end
for j=2:s(2)
logic2 = strcmp(city2,distances{1,j});
if logic2 == true
num2=j;
break
end
end
if num1==0 || num2==0
distance=-1;
return
end
distance=distances{num1,num2};
end

7 件のコメント

What happens if the file is not exactly 337 rows?
i fixed it
What are the possible values returned by strcmp()?
What are the possible values returned by the expression
logic == true
?
Under what circumstances does "if" consider the expression to succeed?
it returns 0 or 1
if it is 1, num=i and breaks the loop
what does the flag mark mean?
Rik
Rik 2021 年 3 月 29 日
You mean that one? You can use it to attract the attention of high reputation users and site administrators to solve a particular issue (e.g. if a post should be deleted or a thread should be closed).
Also, strcmp doesn't just return 1 or 0, it returns true or false. And it doesn't always return 1 value.
To refrase Walter's second question: when is false equal to true or is true not equal to true?
Use the debugger to execute your code line by line.
ok, thank you
Abhijeet Singh
Abhijeet Singh 2021 年 5 月 14 日
編集済み: Abhijeet Singh 2021 年 5 月 14 日
function distance = get_distance(x,y)
[~,~,everything] = xlsread('Distances.xlsx');
a = everything(1:size(everything,1),1);
b = everything(1,1:size(everything,2));
for j = 1:size(everything,1)
l=0;
if strcmp(a(j,1),x)
l=j;
break
end
end
for i = 1:size(everything,2)
k=0;
if strcmp( b(1,i),y)
k=i;
break
end
end
if k ~= 0 && l ~= 0
s = everything(l,k);
distance = s{1};
else
distance = -1;
end
end

3 件のコメント

Rik
Rik 2021 年 5 月 15 日
What does this answer add? What does it teach? Why should it not be deleted?
@RikIt is another way to solve the given problem! And it will work even if we add few details in the xlx file.
What would you say is the key difference between your solution and the one above this one?
If you want to educate: comments are a great way to explain what your code is doing.
Also:
a = everything(1:size(everything,1),1);
b = everything(1,1:size(everything,2));
%is equivalent to this:
a = everything(:,1);
b = everything(1,:);
function distance = get_distance(c1,c2);
% reads excel file in just everything
[~,~,everything] = xlsread('Distances.xlsx');
% find would give index of c1 readinf first column
a = find(strcmp(everything(1,1:end),c1))
% find would give index of c2 reading first row
% strcmp = are equals two strings inputs?
b = find(strcmp(everything(1:end,1),c2))
% if any c1 or c2 do not exist
if isempty(a) || isempty(b)
distance = -1
else
% converts from cell class to matrix or double
%the distance value based on index
distance = cell2mat(everything(a,b))
end
function distance = get_distance(a,b)
[num,txt] = xlsread('Distances.xlsx');
x = 0;y = 0;
for i = 2:lenghth(txt)
if strcmp(txt{1,i},a)
x = i;break; % It's better to use break, Because it reduces the running time significantly
end
end
for j = 2:height(txt) % It's better to use a seperated for function for j, Because it reduces the running time significantly too
if strcmp(txt{j,1},b)
y = j;break;
end
end
if ~x || ~y
distance = -1;
else
distance = num(x-1,y-1);
end

2 件のコメント

Rik
Rik 2021 年 11 月 1 日
You are on the right track. I would suggest looking up the numel and size functions (as replacement for height and length, which you misspelled).
I would also suggest looking up ismember, which can further increase performance.
As we have the matrices on the memory, you are right and ismember is better than for. After your comment I tried it and the result is awesome. It brakes the time to half.
Really thank you
Hi folks,
plz check my code and plz tell me if I can improve this.
function distance = get_distance(a,b)
[~, ~, data] = xlsread('Distances.xlsx'); %reading the file and having its full data that is by default raw data in data variable on 3rd aurgument
z = size(data); % Calculating the size as we need to traverse both first coloumn and first row
c = z(1,1); % c = no. of rows
d = z(1,2); % d = no. of coloumn
for i = 2:c % as (1,1) of file is empty so starting from 2 to the length of rows and coloumns
e = strcmp(data{1,i},a); % checking through first row and compare with a
if e == true % if we find the matching then record its index in f and stop the loop through 'break'.
f = i;
break;
end
end
for j = 2:d
k = strcmp(data{j,1},b); % checking through first coloumn and compare with b
if k == true % if we find the matching then record its index in l and stop the loop through 'break'.
l = j;
break;
end
end
if e==true && k==true % if both are true then show the distance at that index(f,l) otherwisr distance = -1
distance = data{f,l};
else
distance = -1;
end

4 件のコメント

variable names could be more descriptive
The result of strcmp is already logical, either true or false. You do not need to == true in the if, you can just
if e
thanks a lot for your valueable comment.
ismember() is easier than looping
ok, I will check how this builtin function works.
I got this solution but the last bit of code seems rather plump, do you have suggestions to improve the code?
function [distance] = get_distance(c1,c2)
raw = readcell('Distances.xlsx');
row1 = raw(1,2:end);
col1 = raw(2:end,1);
ind1 = find(ismember(row1,c1));
ind2 = find(ismember(col1,c2));
if isempty(ind1) || isempty(ind2)
distance = -1;
else
dis = raw(2:end,2:end);
d = dis(ind1,ind2);
distance = cell2mat(d);
end

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2019 年 4 月 17 日

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