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Failure in initial user-supplied objective function evaluation. FSOLVE cannot continue.

Marios Karatiso さんによって質問されました 2019 年 4 月 15 日
最新アクティビティ Marios Karatiso さんによって コメントされました 2019 年 4 月 15 日
Hello, I get the following error when trying to use fsolve:
Error in fsolve (line 218)
fuser = feval(funfcn{3},x,varargin{:});
Caused by:
Failure in initial user-supplied objective function evaluation. FSOLVE cannot continue.
It also prints the following error: Index exceeds matrix dimensions.
Can anyone see where is the error in that situation?
I call the fsolve with that line of code:
sol=fsolve(@set,[1;-1])
The function is the following:
function F=set(x)
Vcc=15;
Rth=(100/3)*10^3;
Re=10*10^3;
Rc=20*10^3;
beta_f=100;
beta_R=1;
Is=5*10^(-16);
Vt=0.025;
Voc=10;
F=[x(1)-(-Rth-Re(beta_f+1))*(Is/beta_f)*(exp(x(1)/Vt)-1)-(-Rth+beta_R*Re)*(Is/beta_f)*(exp(x(2)/Vt)-1)+Voc;
x(2)-(-Rth+Rc*beta_f)*(Is/beta_f)*(exp(x(1)/Vt)-1)-(-Rth-Rc*(beta_R+1))*(Is/beta_f)*(exp(x(2)/Vt)-1)-Vcc+Voc];
end

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1 件の回答

回答者: madhan ravi
2019 年 4 月 15 日
編集済み: madhan ravi
2019 年 4 月 15 日
 採用された回答

Note: Don't name your function set() will shadow the in-built function set().
sol=fsolve(@set1,[1,-1])
function F=set1(x)
Vcc=15;
Rth=(100/3)*10^3;
Re=10*10^3;
Rc=20*10^3;
beta_f=100;
beta_R=1;
Is=5*10^(-16);
Vt=0.025;
Voc=10;
F=[x(1)-(-Rth-Re*(beta_f+1))*(Is/beta_f)*(exp(x(1)/Vt)-1)-(-Rth+beta_R*Re)*(Is/beta_f)*(exp(x(2)/Vt)-1)+Voc;
% ^----- missed it
x(2)-(-Rth+Rc*beta_f)*(Is/beta_f)*(exp(x(1)/Vt)-1)-(-Rth-Rc*(beta_R+1))*(Is/beta_f)*(exp(x(2)/Vt)-1)-Vcc+Voc];
end
Gives:
Equation solved.
fsolve completed because the vector of function values is near zero
as measured by the default value of the function tolerance, and
the problem appears regular as measured by the gradient.
<stopping criteria details>
sol =
-11.3516
0.7520
>>

  2 件のコメント

Sorry the 1 in @set1 was a typo.
Oh that was such a bad mistake thanks a lot...

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